Skip to content

  • Home
  • Mathematics
  • English
  • History
  • Chemistry
  • Biology
  • Law
  • Medicine
  • Business
  • Toggle search form

Suppose a parabola has an axis of symmetry at x = -8 , a maximum height of 2, and passes through the point (-7, -1). write

Posted on October 22, 2021 By Nestergurl101 5 Comments on Suppose a parabola has an axis of symmetry at x = -8 , a maximum height of 2, and passes through the point (-7, -1). write

Suppose a parabola has an axis of symmetry at x = -8 , a maximum height of 2, and passes through the point (-7, -1). write the equation of the parabola in vertex form.

Mathematics

Post navigation

Previous Post: Item 2Read this excerpt from ‘Ormuzd and Arimanes.’Ormuzd, the king of light, and Arimanes, the prince of darkness, both emanated from the Eternal
Next Post: ) Marianne orders a pack of shippingboxes shaped like cubes. When theyarrive, she finds flat pieces of cardboardas shown. What

Comments (5) on “Suppose a parabola has an axis of symmetry at x = -8 , a maximum height of 2, and passes through the point (-7, -1). write”

  1. torrejes241 says:
    October 23, 2021 at 4:38 pm

    As it has a maximum value the coefficient of x^2 will be negative

    The vertex will be at (-8,2)  so in vertex form it is

    y = a(x + 8)^2 + 2
    and as it passes through (-7,-1) we have:

    -1  = a(-7+8)^2 + 2

    -1 = a + 2  so a = -3

    answer is  y = -3(x + 8)^2 + 2

    in standard form this is y = -3x^2 -48x  - 190

    Reply
  2. alisonlebron15 says:
    October 23, 2021 at 5:20 pm

    Its standard form of equation: (x-h)^2=-4p (y-k), (h,k)=(x,y) coordinates of the vertex
    For given parabola: Vertex = (-8, 2)
    (x-(-8))² = -4p(y - 2)

    solve for 4p using coordinates of given point ( -7, -1)
    -7+8  = 4p (-1 - 2)
    1 = 4p(-3)
    4p = -1/3

    So, Equation of given parabola:
    (x+8)² = -(y-2) / 3

    Hope this helps!

    Reply
  3. genyjoannerubiera says:
    October 23, 2021 at 7:10 pm

    Y=-3(x+8)^2+2 Fill in the vertex (-8,2), and the ordered pair(-7.1) then solve for a. Y = a(x-h)^2 + k

    Reply
  4. melanie1055 says:
    October 23, 2021 at 9:23 pm

    What if it doesnt have an axis of symmetry?

    Reply
  5. itsbrizee says:
    October 23, 2021 at 10:07 pm

    we know that

    If an axis of symmetry is [tex]x=-8[/tex] and has a maximum height of [tex]2[/tex]

    then

    Is a vertical parabola open down with vertex at [tex](-8,2)[/tex]

    the equation in vertex form is equal to

    [tex]y=a(x-h)^{2}+k[/tex]

    where

    (h,k) is the vertex

    substitute

    [tex]y=a(x+8)^{2}+2[/tex]

    Find the value of a

    the parabola passes through the point [tex](-7,-1)[/tex]

    substitute in the formula

    [tex]-1=a(-7+8)^{2}+2[/tex]

    [tex]-1=a(1)^{2}+2[/tex]

    [tex]-1=a+2[/tex]

    [tex]a=-3[/tex]

    therefore

    the answer is

    the equation in vertex form is  [tex]y=-3(x+8)^{2}+2[/tex]

    Reply

Leave a Reply Cancel reply

Your email address will not be published. Required fields are marked *

Categories

  • Advanced Placement (AP)
  • Arts
  • Biology
  • Business
  • Chemistry
  • Computers and Technology
  • Engineering
  • English
  • French
  • Geography
  • German
  • Health
  • History
  • Law
  • Mathematics
  • Medicine
  • Physics
  • SAT
  • Social Studies
  • Spanish
  • World Languages

© 2021 studyqas

Powered by PressBook WordPress theme