Suppose f is a polynomial such that f(0) = 47, f(1) = 32, f(2) = -13, and f(3)=16. What is the sum of the coefficients of f?

Skip to content# Suppose f is a polynomial such that f(0) = 47, f(1) = 32, f(2) = -13, and f(3)=16. What is the sum of the coefficients of f?

Suppose f is a polynomial such that f(0) = 47, f(1) = 32, f(2) = -13, and f(3)=16. What is the sum of the coefficients of f?

Mathematics ##
Comments (4) on “Suppose f is a polynomial such that f(0) = 47, f(1) = 32, f(2) = -13, and f(3)=16. What is the sum of the coefficients of f?”

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hi there!

not proportional because the 42 does not go into 120 and 3 does not go into 8.

correct proportion: $40/1 ticket.

the reason i say this is because 40/1 is simplified and it evenly goes into 120/3.

hope this : )

ιт ιѕ:

125.28

нσρє ι ¢συℓρ нєℓρ

the answer to this in exact form is 4/35 but in decimal form its 0.1142857

hope this if needed hmu

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