Home Mathematics Surface area of this figure below? Surface area of this figure below?Mathematics GracebrownnnOctober 23, 20214 CommentsSurface area of this figure below?[tex]Surface area of this figure below?[/tex]
dc=6 square root of 3 and ac is 12 square root 3c and dstep-by-step explanation:square root of 3/2 = 18/ccross multiply to get 18*2=√3*c36/√3 * √3/√3 = cc= 36*√3/3c=12√3Reply
Answer: b 2 = 1.step-by-step explanation: given equation a = h(b 1+b 2)also we are given values of a, h and b 1 as :a = 16, h = 4, and b 1 = 3.in order to solve it for b 2, we need to plug the given values of a, h and b 1 .therefore, plugging values of a, h and b 1 in given equation, we get16 = 4( 3 + b 2)first dividing both sides by 4, we get[tex]\frac{16}{4} =\frac{4( 3 + b 2)}{4}[/tex]4 = 3 + b 2subtracting 3 from both sides, we get4 -3 = 3 -3 + b 21 = b 2.therefore, b 2= 1.Reply
the answer is 99.
r = 78539458390583095803458309458039485093485 or just 3
step-by-step explanation:
dc=6 square root of 3 and ac is 12 square root 3
c and d
step-by-step explanation:
square root of 3/2 = 18/c
cross multiply to get 18*2=√3*c
36/√3 * √3/√3 = c
c= 36*√3/3
c=12√3
Answer: b 2 = 1.
step-by-step explanation: given equation a = h(b 1+b 2)
also we are given values of a, h and b 1 as :
a = 16, h = 4, and b 1 = 3.
in order to solve it for b 2, we need to plug the given values of a, h and b 1 .
therefore, plugging values of a, h and b 1 in given equation, we get
16 = 4( 3 + b 2)
first dividing both sides by 4, we get
[tex]\frac{16}{4} =\frac{4( 3 + b 2)}{4}[/tex]
4 = 3 + b 2
subtracting 3 from both sides, we get
4 -3 = 3 -3 + b 2
1 = b 2.
therefore, b 2= 1.