Team 1 and team 2 had games. Team 1 plays every 3 days and team 2 plays every 5 days. When will both teams have games on the same day again

Skip to content# Team 1 and team 2 had games. Team 1 plays every 3 days and team 2 plays every 5 days. When will both teams have games on the

Mathematics ##
Comments (4) on “Team 1 and team 2 had games. Team 1 plays every 3 days and team 2 plays every 5 days. When will both teams have games on the”

### Leave a Reply Cancel reply

Team 1 and team 2 had games. Team 1 plays every 3 days and team 2 plays every 5 days. When will both teams have games on the same day again

p> q if you calculate p is100 q is 79

[tex]What do you know to be true about the values of p and q?[/tex]

What the heck i didn’t know

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)