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1. The energy of one photon of this light is 4.568 × 10∧ -19 J  

   Explanation:

   Given data:

   wavelength = 433.9 nm or 433.9 × 10∧-9 m

   The value of speed of light is 3× 10∧8 m/s and plancks constant is 6.626 × 10∧-34 m²Kg/s

   Formula:

   E= hc/λ

   E= energy of photon

   h= plancks constant

   c= speed of light

   λ= wavelength of given light

   Solution:

   E= hc / λ

   E = 6.626 × 10∧-34 m²Kg/s × 3× 10∧8 m/s / 433.9 × 10∧-9 m

   E = 19.878 × 10∧-26 m²Kg/s² / 433.9 × 10∧-9 m

   E = 0.04568 × 10∧ -17 J            (Kg m²/s² =J)

   E = 4.568 × 10∧ -19 J  

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2. [tex]\large \boxed{4.578 \times 10^{-19} \text{ J}}[/tex]

   Explanation:

   The formula for the energy of a photon is

   E = hc/λ

   If λ = 433.9 nm, then  

   [tex]\begin{array}{rcl}E & = & \dfrac{6.626 \times 10^{-34} \text{ J$\cdot$s} \times 2.998 \times 10^{8}\text{ s}} {433.9 \times 10^{-9} \text{ m}}\\\\& = & 4.578 \times 10^{-19} \text{ J}\\\end{array}\\\text{The energy of one photon is $\large \boxed{\mathbf{4.578 \times 10^{-19}} \textbf{ J}}$}[/tex]

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