The diameter of a circular field is 56 cm. find the length of wire required to

fence it? how

many times it can be fenced with 704 m of wire ?

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The diameter of a circular field is 56 cm. find the length of wire required to

fence it? how

many times it can be fenced with 704 m of wire ?

length of wire required to

fence is 175.84 cm

4 times

Step-by-step explanation:

P=2rπ

r=56cm/2

r=28cm

P=2*28*3.14

P=175.84cm

704m/175.84 cm= 4

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

[tex]ab^2+ac^2=bc^2[/tex]

[tex]ab^2+ac^2=x^2[/tex] )

triangle abd and cba are similar,

[tex]\frac{ab}{bc}=\frac{bd}{ab}[/tex]

[tex]ab^2=bc\cdot bd[/tex]

[tex]25=bc\cdot bd[/tex] (2)

triangle cad and cba are similar,

[tex]\frac{ac}{bc}=\frac{cd}{ac}[/tex]

[tex]ac^2=bc\cdot dc[/tex]

[tex]7\times 7=bc\cdot dc[/tex]

[tex]49=bc\cdot dc[/tex] )

using (1), (2) and (3), we get

[tex]25+49=x^2[/tex]

[tex]74=x^2[/tex]

hence proved.

therefore option 2 is correct.

20 percentage, you can also do it on a calculator.