For a better understanding of the solution provided here please find the diagram attached.
Please note that in coordinate geometry, the coordinates of the midpoint of a line segment is always the average of the coordinates of the endpoints of that line segment.
Thus, if, for example, the end coordinates of a line segment are [tex](x_{1}, y_1)[/tex] and [tex](x_2, y_2)[/tex] then the coordinates of the midpoint of this line segment will be the average of the coordinates of the two endpoints and thus, it will be:
I guess you are looking for a general way of writing a midpoint in coordinate system. we have the following: E(xe, ye) and F(xf,yf) then mind point is as follows ((xe+xf)/2, (ye+yf)/2)
For a better understanding of the solution provided here please find the diagram attached.
Please note that in coordinate geometry, the coordinates of the midpoint of a line segment is always the average of the coordinates of the endpoints of that line segment.
Thus, if, for example, the end coordinates of a line segment are [tex](x_{1}, y_1)[/tex] and [tex](x_2, y_2)[/tex] then the coordinates of the midpoint of this line segment will be the average of the coordinates of the two endpoints and thus, it will be:
[tex](\frac{(x_1+x_2)}{2}, \frac{(y_1+y_2)}{2})[/tex]
Thus for our question the endpoints are [tex](x_E, y_E)[/tex] and [tex](x_F, y_F)[/tex] and hence the midpoint will be:
[tex](x_M, y_M)=[/tex][tex](\frac{(x_E+x_F)}{2}, \frac{(y_E+y_F)}{2})[/tex]
Thus, Option C is the correct option.
[tex]The endpoints of `bar(ef)` are e(xe , ye) and f(xf , yf). what are the coordinates of the midpoint o[/tex]
X1 + x2/2 , y1 = y2/2
xE + xF/2 , yE + yF/2
So it is C or D, becuase they are the same answer choices
The coordinates of the midpoint of EF are:
M ( [tex]\frac{xE+xF}{2}, \frac{yE+yF}{2}[/tex] )
The coordinates of the midpoint of EF is equal to
[tex](\frac{xE+xF}{2},\frac{yE+yF}{2})[/tex]
Step-by-step explanation:
we know that
The formula to calculate the midpoint between two points is equal to
[tex]M=(\frac{x1+x2}{2},\frac{y1+y2}{2})[/tex]
In this problem we have
[tex](x1,y1)=(xE,yE)[/tex]
[tex](x2,y2)=(xF,yF)[/tex]
Substitute the values in the formula
[tex]M=(\frac{xE+xF}{2},\frac{yE+yF}{2})[/tex]
The correct option is (D) [tex]\left(\dfrac{xE+xF}{2},\dfrac{yE+yF}{2}\right).[/tex]
Step-by-step explanation: Given that the co-ordiantes of the end-points of segment EF are E(xE, yE) and F(xF, yF) respectively.
To find the co-ordinates of the mid-point of EF.
We know that
the co-ordinates of the mid-point of a line segment with end-points A(a, b) and B(c, d) are given by
[tex]\left(\dfrac{a+c}{2},\dfrac{b+d}{2}\right).[/tex]
Therefore, the co-ordinates of the mid-point of segment Sf will be
[tex]\left(\dfrac{xE+xF}{2},\dfrac{yE+yF}{2}\right).[/tex]
Thus, (D) is the correct option.
I guess you are looking for a general way of writing a midpoint in coordinate system.
we have the following:
E(xe, ye) and F(xf,yf)
then mind point is as follows
((xe+xf)/2, (ye+yf)/2)
(xE+yE/2) + (xF+yF/2)