# The end points ef are e(xe, ye) and f(xf, yf). what are the coordinates of the midpoint ef?

The end points ef are e(xe, ye) and f(xf, yf). what are the coordinates of the midpoint ef?

## This Post Has 7 Comments

1. theirishgold42 says:

For a better understanding of the solution provided here please find the diagram attached.

Please note that in coordinate geometry, the coordinates of the midpoint of a line segment is always the average of the coordinates of the endpoints of that line segment.

Thus, if, for example, the end coordinates of a line segment are $(x_{1}, y_1)$ and $(x_2, y_2)$ then the coordinates of the midpoint of this line segment will be the average of the coordinates of the two endpoints and thus, it will be:

$(\frac{(x_1+x_2)}{2}, \frac{(y_1+y_2)}{2})$

Thus for our question the endpoints are $(x_E, y_E)$ and $(x_F, y_F)$ and hence the midpoint will be:

$(x_M, y_M)=$$(\frac{(x_E+x_F)}{2}, \frac{(y_E+y_F)}{2})$

Thus, Option C is the correct option.

$The endpoints of $bar(ef)$ are e(xe , ye) and f(xf , yf). what are the coordinates of the midpoint o$

2. aiselsarmientop8o290 says:

X1 + x2/2 , y1 = y2/2

xE + xF/2 , yE + yF/2

So it is C or D, becuase they are the same answer choices

3. aaayymm says:

The coordinates of the midpoint of EF are:
M ( $\frac{xE+xF}{2}, \frac{yE+yF}{2}$ )

4. billey32 says:

The coordinates of the midpoint of EF is equal to

$(\frac{xE+xF}{2},\frac{yE+yF}{2})$

Step-by-step explanation:

we know that

The formula to calculate the midpoint between two points is equal to

$M=(\frac{x1+x2}{2},\frac{y1+y2}{2})$

In this problem we have

$(x1,y1)=(xE,yE)$

$(x2,y2)=(xF,yF)$

Substitute the values in the formula

$M=(\frac{xE+xF}{2},\frac{yE+yF}{2})$

5. cardsqueen says:

The correct option is (D) $\left(\dfrac{xE+xF}{2},\dfrac{yE+yF}{2}\right).$

Step-by-step explanation:  Given that the co-ordiantes of the end-points of segment EF are E(xE, yE) and F(xF, yF) respectively.

To find the co-ordinates of the mid-point of EF.

We know that

the co-ordinates of the mid-point of a line segment with end-points A(a, b) and B(c, d) are given by

$\left(\dfrac{a+c}{2},\dfrac{b+d}{2}\right).$

Therefore, the co-ordinates of the mid-point of segment Sf will be

$\left(\dfrac{xE+xF}{2},\dfrac{yE+yF}{2}\right).$

Thus, (D) is the correct option.

6. bhjbh7ubb says:

I guess you are looking for a general way of writing a midpoint in coordinate system.
we have the following:
E(xe, ye) and F(xf,yf)
then mind point is as follows
((xe+xf)/2, (ye+yf)/2)

7. kayla941 says:

(xE+yE/2) + (xF+yF/2)