The following dot plots represent the scores on the Chapter 5 quiz for Mrs. Chin's 4th and 6th-period classes. 1. Calculate the mean and mean absolute deviation (rounded to the nearest tenth) for both classes.

2. Use your answer calculations from part A to answer all of the following questions: Which class period, on average, scored better on the quiz? By how much did they score better? How does the difference between the mean scores compare to the mean absolute deviation? Is there much overlap in the data? Write your answers in complete sentences.

[tex]The following dot plots represent the scores on the Chapter 5 quiz for Mrs. Chin's 4th and 6th-peri[/tex]

step-by-step explanation:

what was your answer?

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph

there is a hike in both the graphs so the graphs are increasing on their domain.x-intercept of log x and log 6x are differentthere is a vertical asymptote of both the graphs so there is no y-interceptas both the graphs are increasing so there is no horizontal asymptote

1/2(2*4)=6 $$- agahajakanajak

y∈r, 8> y≥0

hope i !

p.s the first bit only matters if you know what that means.

p.p.s brainliest would really