The length of a rectangle is 4 centimeters more than twice its width of the perimeter of the rectangle is 86centimeters find the dimensions of the rectangle

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The length of a rectangle is 4 centimeters more than twice its width of the perimeter of the rectangle is 86centimeters find the dimensions of the rectangle

X=13

Hope i helped you out. your welcome. peace

width = 13

length = 30

p=2l + 2w

86 = 2(2w+4) + 2w

86 = 4w + 8 + 2w

86= 6w + 8

78 = 6w

13 = w

86 = 2l + 2(13)

86 = 2l + 26

60 = 2l

30 = l

check your work.

l is 4 centimeters more than twice w

twice w = 26

plus 4 = 30

i hope you understand. ask questions if not

Rectangle formula 1/2 ×b × H × l

= 1

___ × 4 × 86 × 2 = 344 totally answer

2

P = perimeter = 2L + 2W = 86 cm. Also, L = W + 4. Subst. W + 4 for L,

P = 2(W + 4) + 2W = 86 cm. Then 2W + 8 + 2W = 86 cm, and 4W = 78 cm.

Finally solving for W, W = (78 cm)/4, or 19.5 cm.

If W = 19.5 cm, then L = W + 4 cm = 19.5 cm + 4 cm = 23.5 cm

The rectangle's dimensions are 19.5 cm by 23.5 cm.

[tex]Width= 13 cm[/tex]

[tex]length=30cm[/tex]

Step-by-step explanation:

Let the length of the rectangle be 'L'

And the width of the rectangle be 'W'

[tex]Perimeter= 86 cm[/tex]

According to the statement:

[tex]Length= 2*Width+4\\L=2W+4[/tex]

Perimeter of a rectangle= 2(Length+Width)

[tex]86=2(2W+4+W)\\86/2=3W+4\\43=3W+4\\3W=43-4\\3W=39\\W=39/3\\W=13 cm\\\\Length(L)=2W+4\\=2(13)+4=26+4=30 cm\\Length=30 cm[/tex]

[tex]Width= 13 cm[/tex]

[tex]length=30cm[/tex]