# The number of purses a vendor sells daily has the probability distribution represented in the table.

The number of purses a vendor sells daily has the probability distribution represented in the table. Number of Purses, x 0 1 2 3 4 5 P(x) 0.35 0.15 0.2 0.2 0.03 0.07 If each purse sells for $50.00, what is the expected daily total dollar amount taken in by the vendor from the sale of purses?$1.62 $35.00$79.30 $81.00$162.00

## This Post Has One Comment

1. bethzabezarahi says:

(D)$81 Step-by-step explanation: Given that the number of purses a vendor sells daily has the probability distribution represented in the table. Expected Value, $E(x)=\sum_{i=1}^{n}x\cdot p(x)$ Therefore: $E(x)=(0X0.35)+(1X0.15)+(2X0.2)+(3X0.2)+(4X0.03)+(5X0.07)\\=0+0.15+0.4+0.6+0.12+0.35\\E(x)=1.62$ If each purse sells for$50.00, the number of expected daily total dollar amount taken in by the vendor from the sale of purses

=Expected Value X $50 =1.62 X$50

=\$81

The correct option is D.