the side of an equilateral triangle is
measured as 7 cm to the nearest centimetre.
what are the greatest and least possible
lengths of the side of the triangle? use these
values to calculate the greatest and least
possible values of the area of the triangle.
your answers to the nearest 0-1 cm
The expression for the perimeter as well as the choices are not properly shown. Therefore, I cannot give you an exact answer.
However, I can help you with the concept.
In an equilateral triangle:
1- All sides are equal
2- All angles are equal
The perimeter of any triangle can be calculated as follows:
perimeter = first side + second side + third side
Since the three sides of an equilateral triangle are equal and assuming that each has a length of s units, the perimeter would be:
perimeter = s + s + s
perimeter = 3s
Now, if we are given the perimeter and we want to get the side length. all we have to do is divide the perimeter by 3.
Examples:
1- If the perimeter is 60:
side length = 60/3 = 20 units
2- If the perimeter is 6x + 15
side length = (6x+15) / 3 = 2x + 5 units
Hope this helps 🙂
13 inches
Step-by-step explanation:
c
Step-by-step explanation:
The altitude of an equilateral triangle:
h = s √3 / 2, where s is the length of one side of the triangle.
s √3 /2 = 7 √ 3 / : √3
s / 2 = 7
s = 7 * 2
s = 14 units
B ) 14
Side of triangle = 13 inches
Step-by-step explanation:
Let side of square be x inches.
Perimeter of square = 4*side = 4x >1
side of triangle = x+5 { the side of the triangle is 5 inches more than the side of the square. }
Perimeter of triangle = 3*side
= 3 * (x+5) =3x + 15 >2
The perimeter of an equilateral triangle is 7 inches more than perimeter of a square.
3x + 15 - 4x = 7
3x -4x = 7-15
-x = - 8
x= 8
Side of a square = 8 inches.
Side of triangle = x + 5 = 8 + 5 = 13 inches
The answer is 7. Hope this helps.
The answer is B. perimeter: 16.2; area 10.1 m2
top option
Step-by-step explanation:
Since A=1/2 (b) (h) then: 5.4 x 4.7 /2=12.69 or 12.7; P= a+b+c P= 5.4 x 3 =16.2 . It is an equilateral triangle meaning all the sides are equal.
so; P= 16.2 m & A= 12.7 m2
Let [tex]t[/tex] be the side of the triangle and [tex]s[/tex] be the side of the square.
Let [tex]P_t[/tex] be the perimeter of the triangle and [tex]P_s[/tex] be the perimeter of the square.
We have the following relationship:
[tex]\begin{cases}P_t = P_s+7\\t=s+5\\P_t = 3t\\P_s=4s\end{cases} \implies \begin{cases}3t=4s+7\\t=s+5\end{cases} \implies 3(s+5)=4s+7 \implies s=8[/tex]
Which finally implies
[tex]t=s+5=13[/tex]
The answer to your question is x = 9
Step-by-step explanation:
Data
Side of a square = s = x + 3
Side of a triangle = s = x + 7
Perimeter of a square = 4s
Perimeter of a triangle = 3s
Process
1.- Consider both perimeters are equal
Perimeter of a square = Perimeter of a triangle
2- Substitution
4(x + 3) = 3(x + 7)
3.- Expand
4x + 12 = 3x + 21
4.- Solve for x
4x - 3x = 21 - 12
x = 9