The sum of three consecutive even integers is -114. what is the least of these numbers? a. 40 b. -36 c. -40 d. -44

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The sum of three consecutive even integers is -114. what is the least of these numbers? a. 40 b. -36 c. -40 d. -44

24+x=y

step-by-step explanation:

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23

Let the integers be;

x, x+2, x+4

The sum is;

x+x+2+x+4=-114

3x+6=-114

3x=-114-6

3x=-120

x=-40

The least integer is thus -40

40 is the largest number !

36 , 38 & 40 are the consecutive numbers having sum of 114 !

Step-by-step explanation:

• A consecutive numbers means number are in a sequence and are one after the another !

• A consecutive even numbers differ by 2 because all even numbers are divisible by 2 !

• If the number is divisible by x we must had taken number as n , ( n + x ) ,

( n + 2x )

Let the consecutive even numbers be n ( n + 2 ) and ( n + 4 )

Given :- Sum of the numbers is 114

n + n + 2 + n + 4 = 114

3n + 6 = 114

3n = 114 - 6

3n = 108

n = 108/3

n = 36

So, the Consecutive even numbers are :-

n = 36

n + 2 = 36 + 2 = 38

n + 4 = 36 + 4 = 40

So, the Largest number is 40 !!

• Verification :-

36 + 38 + 40 = 114

Hence, it satisfies the given condition !

so, verified !

36,38 and 40 are the three consecutive even integers

Step-by-step explanation:

As we Know that we have three consecutive even integers and even integers can be Obtained by adding or subtracting 2 from the given Number

Now According to the given condition we have three consecutive even integers

Let First even integer be x

Second even integer would be x + 2

Third even integer would be x + 2 + 2 = x + 4

Now According to the first condition

Sum of three integers = 114

so it would become

x + ( x + 2 ) + ( x + 4)=114 (i)

This would be the equation

Solving it

x + x + 2 + x + 4 = 114

3x + 6 =114

subtracting 6 from both sides

3x + 6 - 6 = 114 -6

3x = 108

Dividing both sides by 3

x = 108 /3

x = 36

Now second integer = x + 2 and third integer = x + 4

Putting the value of x

Second integer = 36 + 2 third integer = 36 +4

= 38 = 40

So three consecutive even integers are 36,38 and 40

The sum of three consecutives is b