To do this we need to calculate: [tex]22 \frac{1}{20} - 8 \frac{1}{2} - 5 \frac{1}{4}[/tex] [tex]= \frac{441}{20} - \frac{17}{2} - \frac{21}{4}[/tex] Then we need to convert these to all have a common denominator: [tex]= \frac{441}{20} - \frac{170}{20} - \frac{105}{20}[/tex] [tex]= \frac{441-170-105}{20}[/tex] [tex]= \frac{166}{20}[/tex] [tex]= 8 \frac{6}{20}[/tex] [tex]= 8 \frac{3}{10}[/tex]
all about the same size in the city the game was
step-by-step explanation:
Make all mixed number improper fractions first...
rule: a b/c=(ac+b)/c
22 1/20=8 1/2+5 1/4+n
441/20=17/2+21/4+n make all have a common denominator of 20
441/20=170/20+105/20+20n/20 multiply both sides by 20
441=170+105+20n combine like terms
441=275+20n subtract 275 from both sides
166=20n divide both sides by 20
n=166/20 and we can convert this back to a mixed number...
n=(160+6)/20
n=8+6/20
n=8 3/10
Deja qué x = longitud6(x) = 48cm^2divide por 6: x = 8la área de longitud es 8 cm.
To do this we need to calculate:
[tex]22 \frac{1}{20} - 8 \frac{1}{2} - 5 \frac{1}{4}[/tex]
[tex]= \frac{441}{20} - \frac{17}{2} - \frac{21}{4}[/tex]
Then we need to convert these to all have a common denominator:
[tex]= \frac{441}{20} - \frac{170}{20} - \frac{105}{20}[/tex]
[tex]= \frac{441-170-105}{20}[/tex]
[tex]= \frac{166}{20}[/tex]
[tex]= 8 \frac{6}{20}[/tex]
[tex]= 8 \frac{3}{10}[/tex]