The supplement of the complement of an angle less the complement of an angle exceeds

The supplement of the complement of an angle less the complement of an angle exceeds the quotient of the supplement of the angle and the number 3 by 73. find the angle.

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  1. Supplementary angles are those which sum upto 180°

    [tex]\angle 1+\angle2=180^{\circ}[/tex]

    Complementary are those which sum to 90°

    [tex]\angle 1+\angle2=90^{\circ}[/tex]

    so if you know one angle, you can find other.

  2. complement is 78°, supplement is 168°

    Step-by-step explanation:

    Part 1) Find the measure of the complement

    we know that

    If two angles are complementary, then their sum is equal to 90 degrees

    Let

    C ----> the complement of the given angle

    we have

    [tex]m\angle G=12^o[/tex]

    so

    [tex]m\angle G+m\angle C=90^o[/tex]

    substitute

    [tex]12^o+m\angle C=90^o[/tex]

    [tex]m\angle C=90^o-12^o=78^o[/tex]

    Part 2) Find the measure of the supplement

    we know that

    If two angles are supplementary, then their sum is equal to 180 degrees

    Let

    S ----> the supplement of the given angle

    we have

    [tex]m\angle G=12^o[/tex]

    so

    [tex]m\angle G+m\angle S=180^o[/tex]

    substitute

    [tex]12^o+m\angle S=180^o[/tex]

    [tex]m\angle S=180^o-12^o=168^o[/tex]

  3. The correct answer would C. Complement 70. supplement 160.

    Step-by-step explanation:

    60+B+B=9060–60+B+B=90–60B+B=302B=302÷2B=30÷2B=15

    Therefore, since A=B+60 then  A=15+60 which equals 70 . SO the answer would C.

    * Hopefully this helps:) Mark me the brainliest:)

  4. Look at my explaination

    Step-by-step explanation:The complement of 50 is 90-50 giving us 40degrees

    The supplement of 145 is 180-145=35 degrees

    The compliment of 27 degrees is 90-27=63 degrees

    The supplement of 50 degrees is 180-50=130 degrees

  5. C) complement, 37°, supplement, 127°

    Step-by-step explanation:

    We know that complementary angles add to 90 degrees

    x+53 =90

    Subtract 53 from each side

    x+53-53=90-53

    x = 37

    We know that supplementary angles add to 180

    x+53 =180

    Subtract 53 from each side

    x+53-53= 180-53

    x = 127

  6. But i think

    Complemantary are angles whose sum is 90 and supplementary are the ones whose sum is 180

    So
    Complementary of 60 is 30
    And
    Supplementary is 120

    Pleasee tell where i m wrong but this is what i studied and i am sure its correct

  7. Complement of an angle = 90° - x.

    Supplement of the complement of an angle = 180 - (90 - x).

    = 180 - 90 + x

    = 90 + x

    Supplement of the complement of an angle less the complement of an angle = (90 + x) - (90 - x)

    = 90 + x - 90 + x

    = 2x

    Now, the quotient of the supplement of the angle and the number 3 is [tex]\frac{180-x}{3}[/tex].

    It is given that supplement of the complement of an angle less the complement of an angle exceeds the quotient of the supplement of the angle and the number 3 by 73.

    Therefore, 2x = [tex]\frac{180x}{3} +73[/tex]

    [tex]2x=\frac{180-x+219}{3}[/tex]

    Multiply both sides by 3.

    6x = 180 - x + 219

    = 399 - x

    Add x to both sides.

    6x + x = 399

    7x = 399

    Divide both sides by 7.

    x = 57

    Hence, the required angle = 57°.

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