The vertices of quadrilateral MNPQ are M(−7,−2),N(−5,2),P(−3,1), and Q(−6,−3). Translate quadrilateral MNPQ using the vector ⟨−1,5⟩. The vertices of M′N′P′Q′ after the translation are?

Skip to content# The vertices of quadrilateral MNPQ are M(−7,−2),N(−5,2),P(−3,1), and Q(−6,−3). Translate quadrilateral MNPQ

Mathematics ##
Comments (4) on “The vertices of quadrilateral MNPQ are M(−7,−2),N(−5,2),P(−3,1), and Q(−6,−3). Translate quadrilateral MNPQ”

### Leave a Reply Cancel reply

The vertices of quadrilateral MNPQ are M(−7,−2),N(−5,2),P(−3,1), and Q(−6,−3). Translate quadrilateral MNPQ using the vector ⟨−1,5⟩. The vertices of M′N′P′Q′ after the translation are?

the least common denominatore of 7 and 2 is 9

step-by-step explanation:

7+2=9

x² + 3x + 7 = 0 [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

[tex]x = \frac{-b+/-\sqrt{b^2-4ac} }{2a}[/tex] (+/- is this ±)

plug in the numbers into the variables

[tex]x = \frac{-3+/-\sqrt{3^2-4(1)(7)} }{2(1)}[/tex]

[tex]x=\frac{-3+/-\sqrt{9-28} }{2}[/tex]

[tex]x=\frac{-3+/-\sqrt{-19} }{2}[/tex]

your answer is a

[tex]What is the solution to this equation? x^2+3x+7=0[/tex]

see below

step-by-step explanation:

x+2> 6

subtract 2 from each side

x+2-2 > 6-2

x > 4

there is an open circle at 4 since is it is greater than and the line goes to the right

[tex]Which graph represents the solution set of the inequality x+2> 6[/tex]

answer: your answer is c

step-by-step explanation:

[tex]Asap a b c or d **if you know it answer, if not don’t waist my time**[/tex]