The volume of a box v is given by the formula v=lwh, where l is length, w is width, and h is height.

a) solve for h

b) what is the height of the box with a volume of 50 cubic maters, length of 10 meters, and width of 2 meters.

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a) solve for h

b) what is the height of the box with a volume of 50 cubic maters, length of 10 meters, and width of 2 meters.

1)Original Equation: V=lwh

Divide by lw: V/w=lw/lw(h)

h= V/lw

2)Set up the equation as V=lwh

Substitute the variables for numbers: 50=10(2)h

Multiply 10*2: 50=20h

Divide 50each side by 20 to get rid of 20h: 50/20=20/20

H=2.5

The height of the box is 2.5 meters tall.

y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x y

0 0

1 -3

3 -9

-2 6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.

a) 0.25x times 3. (could be wrong on equation.)

b) 2.25 pound of dark chocolate. (can i eat all the chocolate? plz? anyway, again, could be wrong, but i hope im right. all the chocolate together should be 5.25 pounds)

have a good day!

A. [tex]h=\frac{V}{lw}[/tex]

B. 2.5 meters.

Step-by-step explanation:

We have been given that the volume of a box V is given by the formula [tex]V=lwh[/tex], where l is length, w Is width, and h is height.

(A). Let us solve for h using opposite operations.

[tex]V=lwh[/tex]

Switch sides:

[tex]lwh=V[/tex]

Upon dividing both sides by [tex]lw[/tex], we will get:

[tex]\frac{lwh}{lw}=\frac{V}{lw}[/tex]

[tex]h=\frac{V}{lw}[/tex]

Therefore, the value of h would [tex]\frac{V}{lw}[/tex].

(B). To find height of the box, we will substitute [tex]V=50\text{ m}^3[/tex], [tex]l=10\text{ m}[/tex], and [tex]w=2\text{ m}[/tex].

[tex]h=\frac{50\text{ m}^3}{10\text{ m}\times 2\text{ m}}[/tex]

[tex]h=\frac{50\text{ m}^3}{20\text{ m}^2}[/tex]

[tex]h=\frac{5\text{ m}}{2}[/tex]

[tex]h=2.5\text{ m}[/tex]

Therefore, the height of box is 2.5 meters.