the width of a rectangle is 2 more than 4 times its length. The perimeter of the rectangle is 24 centimeters. Find the width of the rectangle

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the width of a rectangle is 2 more than 4 times its length. The perimeter of the rectangle is 24 centimeters. Find the width of the rectangle

I thinks is

A is the best answer

length=10 feet

Step-by-step explanation:

if you take your 2 widths and add them its 4. then take your perimiter and subtract 4 from it then divide by 2 which is 10 feet

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Plz write ur exam paper urself...

Width = x

Length = x +2

Perimeter = 24

Area = Width • Length = ?

Perimeter = 24 = 2(x +2) + 2(x)

= 2x + 4 + 2x

= 4x + 4

= 20 = 4x

= 5 = x

Width = x = 5, therefore Length = (5) + 2 = 7

Area = Width • Length = 5 • 7 = 35

Area = 35 yards

1) w= (a-2L)÷ 2

2)width= 6

Step-by-step explanation:

W=4L+2, L=(W-2)/4

P=2(L+W)=24

2((W-2)/4+W)=24

2(5W-2)/4=24

5W-2=48

5W=50

W=10