# There are 3 strawberry ice creams, 4 chocolate ice creams, and 7 vanilla ice creams on a tray. barbara

There are 3 strawberry ice creams, 4 chocolate ice creams, and 7 vanilla ice creams on a tray. barbara selects 2 ice creams at random without replacement. what is the probability that she selects 2 chocolate ice creams? independent or dependent?

## This Post Has 3 Comments

1. alous2373 says:

14.29 percent probability or 2 out of 14. Dependent variable.

2. aredding6282 says:

3 strawberry, 4 chocolate, 7 vanilla...total of 14

probability of 1st pick being chocolate = 4/14 reduces to 2/7
without replacing
probability of 2nd pick being chocolate = 3/13

probability of both = 2/7 * 3/13 = 6/91 <==

3. nate1808 says:

There are 14 ice cream all in all. Choosing two out of the 14 ice cream can be determine by the equation,
14C2 = 91
Then, there are 4 chocolate ice creams. Choosing two out of the 4 ice cream id determined through the equation,
4C2 = 6
Thus, the probability that she selects 2 chocolate ice cream is equal to 6/91.