There are 3 strawberry ice creams, 4 chocolate ice creams, and 7 vanilla ice creams on a tray. barbara selects 2 ice creams at random without replacement. what is the probability that she selects 2 chocolate ice creams? independent or dependent?

Skip to content# There are 3 strawberry ice creams, 4 chocolate ice creams, and 7 vanilla ice creams on a tray. barbara

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There are 3 strawberry ice creams, 4 chocolate ice creams, and 7 vanilla ice creams on a tray. barbara selects 2 ice creams at random without replacement. what is the probability that she selects 2 chocolate ice creams? independent or dependent?

14.29 percent probability or 2 out of 14. Dependent variable.

3 strawberry, 4 chocolate, 7 vanilla...total of 14

probability of 1st pick being chocolate = 4/14 reduces to 2/7

without replacing

probability of 2nd pick being chocolate = 3/13

probability of both = 2/7 * 3/13 = 6/91 <==

There are 14 ice cream all in all. Choosing two out of the 14 ice cream can be determine by the equation,

14C2 = 91

Then, there are 4 chocolate ice creams. Choosing two out of the 4 ice cream id determined through the equation,

4C2 = 6

Thus, the probability that she selects 2 chocolate ice cream is equal to 6/91.