Two small bubbles that each have a radius of 3 centimeters collide and merge into one large bubble. The area of
the large bubble is equal to the sum of the areas of the two small
bubbles. To the nearest centimeter, what is the radius of the large
bubble?
Use 3.14 for Pi
find area of 1 small bub
πr² = 3.14 × 3²
= 28.26 cm
area of 2 small bub
28.26 × 2 = 56.52 cm
area of big bub = area of 2 small bub
= 56.52
find radius by using formula
πr² = 56.52
r² = 56.52 ÷ 3.14
r² = 18
r = √18
r = 4.24 cm
round off to nearest cm
4.24 ≈ 4 cm
thats not a system of equations, that is a solution
the answer is thin because within context, the stanza concludes the and frail tone the people have toward each other, and the fact that it would be thin, makes the most sense compared to "pliable" or "not hard or firm to the touch". hope this , good luck.
step-by-step explanation:
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