Two small bubbles that each have a radius of 3 centimeters collide and merge into one large bubble. The area of

the large bubble is equal to the sum of the areas of the two small

bubbles. To the nearest centimeter, what is the radius of the large

bubble?

Use 3.14 for Pi

find area of 1 small bub

πr² = 3.14 × 3²

= 28.26 cm

area of 2 small bub

28.26 × 2 = 56.52 cm

area of big bub = area of 2 small bub

= 56.52

find radius by using formula

πr² = 56.52

r² = 56.52 ÷ 3.14

r² = 18

r = √18

r = 4.24 cm

round off to nearest cm

4.24 ≈ 4 cm

thats not a system of equations, that is a solution

the answer is thin because within context, the stanza concludes the and frail tone the people have toward each other, and the fact that it would be thin, makes the most sense compared to "pliable" or "not hard or firm to the touch". hope this , good luck.

step-by-step explanation:

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