Uhave $20 to spend on taxi fare. the ride costs $5 plus $2.50 per mile.

let m represent the number of miles ridden. write an inequality to determine how many miles you can ride for$20

Skip to content# Uhave $20 to spend on taxi fare. the ride costs $5 plus $2.50 per mile. let m represent the number of miles ridden. write

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Uhave $20 to spend on taxi fare. the ride costs $5 plus $2.50 per mile.

let m represent the number of miles ridden. write an inequality to determine how many miles you can ride for$20

6km in total. That’s it i have to type extra cause makes me to

$2.50d+$5 is your answer

2.5d+5< or equal to 0

($2.50k) + $5

The distance you can ride is 6 kilometers.

($2.50 x 6) + $5 = $20

5+2.50x=20. per means x. 5 is b. 20 is your y.

it has to be u

In total you have $20.

Base fare of taxi is $5.

Per mile cost is $2.50.

Your total cost is [tex]5+2.5x[/tex] where x is the number of miles. Since you're on a budget of maximum $20, the cost should be less than or equal to $20. We can write:

[tex]5+2.5x\leq 20[/tex]

To find how many miles we can write, let's solve the inequality:

[tex]5+2.5x\leq20\\2.5x\leq20-5\\2.5x\leq15\\x\leq\frac{15}{2.5} \\x\leq6[/tex].

This means 6 is the maximum number of miles you can ride with $20.

ANSWER: Maximum 6 miles

$2.5x+$5.00=$20

x=6

2.5(6) + 5

15 + 5

20

The answer is 6

[tex]2.50d+5\leq 20[/tex]

Step-by-step explanation:

Let d represent distance in kilometers.

We have been given that a taxi ride costs $2.50 per kilometer, so the cost of d kilometers would be [tex]2.50d[/tex] dollars.

We are also told that ride costs a fixed charge of $5, so total cost of d kilometers would be [tex]2.50d+5[/tex] dollars.

You have $20 to spend on taxi fare, so the total cost of riding d kilometers should be less than or equal to 20.

We can represent this information in an inequality as:

[tex]2.50d+5\leq 20[/tex]

Therefore, our required inequality would be [tex]2.50d+5\leq 20[/tex].

d = 6 km

Step-by-step explanation:

The total cost of a ride includes a fixed, up-front cost and a variable cost:

C(x) = $5.00 + ($2.50/km)x, where x is the number of kilometers covered.

Setting C(x) = $20, we get:

$20 = $5 + ($2.50/km)x

which needs to be solved for x:

$15 = ($2.50/km)x

Dividing both sides by ($2.50/km) yields

6 km = d