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  1. 8


    From the question given above, the following data were obtained:

    t–butyl ion = (CH₃)₃C⁺

    Number of valence electron =?

    The valence electron(s) talks about the combining power of an element or compound as the case may be.

    Considering the t–butyl ion, (CH₃)₃C⁺ we can see that it has a charge of +1 indicating that it has given out 1 electron to attain the stable octet configuration which has a valence electrons of 8. Thus, the valence electron of t–butyl ion, (CH₃)₃C⁺ is 8

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