Use the angle in the unit circle to find the value of the three trigonometric functions below.

[tex]Use the angle in the unit circle to find the value of the three trigonometric functions below.[/tex]

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Use the angle in the unit circle to find the value of the three trigonometric functions below.

[tex]Use the angle in the unit circle to find the value of the three trigonometric functions below.[/tex]

Just took the quiz.

A. 145°

C. /

A. 250°

D. -.87,-0.5

A. Sqrt(3)/2

cos(270)= 0

sin(270)=-1

tan(270)= undefined

cos(0)=1

sin(0)= 0

tan(0)= 0

idk lol xd

step-by-step explanation:

ez do it yourself lazy

300b(x) is graphed by the functio

A and bc i said so djjcuxydgskd

QUESTION 1

For this first question, we need to measure the angle from the positive x-axis up to the terminal side, which is in the second quadrant.

The measure of the angle

[tex]= 90 + 55[/tex]

[tex]= 145 \degree[/tex]

The correct answer is A.

QUESTION 2

First let us find the acute angle in the fourth quadrant.

This is given by

[tex]\tan( \theta) = \frac{ \frac{1}{2} }{ \frac{ \sqrt{3} }{2} }[/tex]

This implies that,

[tex]\tan( \theta) =\frac{1}{ \sqrt{3} }[/tex]

[tex]\theta=arctan(\frac{1}{ \sqrt{3} })[/tex]

[tex]\theta=30 \degree[/tex]

The angle in standard position

[tex]=( 360 - \theta) \degree[/tex]

[tex]= 330 \degree[/tex]

We measure from the positive x-axis in the anticlockwise direction.

The correct answer is B.

QUESTION 3

Coterminal angles are angles in standard position that have the same terminal side.

To find angles that are coterminal with

[tex]- 110 \degree[/tex]

We either add or subtract 360°.

Since we want the to be between 0° and 360°, we have to add 360° to get,

[tex]- 110 + 360 = 250 \degree[/tex]

The correct answer is A.

QUESTION 4

The acute angle that

[tex]210 \degree[/tex]

makes with the x-axis is 30°.

Since 210 is in the third quadrant, both the sine and cosine ratio are negative.

This implies that,

[tex]\cos(210 \degree) = - \cos(30 \degree)[/tex]

[tex]\sin(210 \degree) = - \sin(30 \degree)[/tex]

Using the special angles,

[tex]\cos(210 \degree) = - \frac{ \sqrt{3} }{2}[/tex]

[tex]\sin(210 \degree) = - \frac{1}{2}[/tex]

Or

[tex]\cos(210 \degree) = - 0.87[/tex]

[tex]\sin(210 \degree) = - 0.5[/tex]

The correct answer is D.

QUESTION 5

The acute angle that 120° makes with the x-axis is 60°.

Since 120° is in the second quadrant, the sine ratio is positive.

This implies that,

[tex]\sin(120 \degree) = \sin(60 \degree)[/tex]

Using special angles, the exact value is,

[tex]\sin(120 \degree) = \frac{\sqrt{3}}{2}[/tex]

The correct answer is A.

0

-1

-inf

1

0

0

repectively

cos(270)= 0

sin(270)=-1

tan(270)= undefined

cos(0)=1

sin(0)= 0

tan(0)= 0

Step-by-step explanation: