Use the four-step procedure to solve the following problem. how much water must be added to a gallon of 10% saline solution to create a 2% solution?

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Use the four-step procedure to solve the following problem. how much water must be added to a gallon of 10% saline solution to create a 2% solution?

Question says to solve the problem in 4 steps:

1. There is 1 gallon of % solution.

Given that 10% saline solution so answer is "1 gallon of 10% solution."

2. There is % saline in water.

Water is pure so answer is "0% saline in water"

3. The equation is .

(0% of x gallon water) + (10% of 1 gallon saline solution) = 2% of mixture

0(x)+0.10(1)=0.02(1+x)

Hence required equation is 0(x)+0.10(1)=0.02(1+x)

4. The answer is gallons.

Now solve above equation to find value of x

0(x)+0.10(1)=0.02(1+x)

0+0.10=0.02+0.02x

0.10=0.02+0.02x

0.10-0.02=0.02x

0.08=0.02x

0.08/0.02=x

4=x

Hence 4 gallons of water is needed.

Let n be the amount of pure water to be added. then: .02(n+1)=.1.02n+.02=.1.02n=.08n=4 gallons of pure water to be added☺☺☺☺

4 gallons of water.

Step-by-step explanation:

1. There is 1 gallon of 10% solution

2. There is 2% saline in water

3. The equation is 10% of 1 gallon = 2% of solution of x gallons of water + saline

0.1 = 0.02(x + 1)

Subtracting 0.02 from both sides, we get

0.1 -0.02= 0.02x +0.02 -0.02

0.08 = 0.02x

Dividing both sides by 0.02, we get

0.08/0.02 = 0.02x/0.02

x = 4.

4. The answer is 4 gallons of water.

Hope you will understand the concept.

Thank you.

There is 1 gallon of 10% solution.. There is 0% saline in water.. The equation is (0.1)(1)+0.02(x+1) so therefore answer is 4 gallons

We are given that some water is added to a gallon of 10% saline to create 2% solution.

Let us assume x gallons of water is added in 10% of a gallon of saline.

Therefore,

10% of 1 gallon = 2 % of (solutions of x gallons of water + saline).

0.1 = 0.02 (x+1)

0.1 = 0.02x +0.02

Subtracting 0.02 from both sides, we get

0.1 -0.02= 0.02x +0.02 -0.02

0.08 = 0.02x

Dividing both sides by 0.02, we get

0.08/0.02 = 0.02x/0.02

x = 4.Therefore, 4 gallons of water must be added to a gallon of 10% saline solution to create a 2% solution.

We have 1 gallon of 10% saline.

How much water (x liters of 0% saline) must be added to make a 2% saline solution?

.10 * 1 + 0x = .02 * (1 +x)

.1 = .02 + .02x

.08 = .02x

x = 4 gallons of water must be added

4 gallons of water should be added in 10% saline solution.

Step-by-step explanation:

Let x gallon of water is added in one gallon of 10% saline solution.

Therefore total volume of 10% saline solution will become (1 + x) gallons

Since concentration of water is 0% so equation will be

0.10(1) + 0(x) = .02(1 + x)

0.10 = 0.02(1 + x)

1 + x = [tex]\frac{0.10}{0.02}[/tex]

x + 1 = 5

x = 5 - 1

x = 4 gallons

Therefore, 4 gallons of water should be added to 10% saline solution to create 2% solution.