Use the four-step procedure to solve the following problem. how much water must be added to a gallon of 10% saline solution to create a 2% solution?
Use the four-step procedure to solve the following problem. how much water must be added to a gallon of 10% saline solution to create a 2% solution?
Question says to solve the problem in 4 steps:
1. There is 1 gallon of % solution.
Given that 10% saline solution so answer is "1 gallon of 10% solution."
2. There is % saline in water.
Water is pure so answer is "0% saline in water"
3. The equation is .
(0% of x gallon water) + (10% of 1 gallon saline solution) = 2% of mixture
0(x)+0.10(1)=0.02(1+x)
Hence required equation is 0(x)+0.10(1)=0.02(1+x)
4. The answer is gallons.
Now solve above equation to find value of x
0(x)+0.10(1)=0.02(1+x)
0+0.10=0.02+0.02x
0.10=0.02+0.02x
0.10-0.02=0.02x
0.08=0.02x
0.08/0.02=x
4=x
Hence 4 gallons of water is needed.
Let n be the amount of pure water to be added. then: .02(n+1)=.1.02n+.02=.1.02n=.08n=4 gallons of pure water to be added☺☺☺☺
4 gallons of water.
Step-by-step explanation:
1. There is 1 gallon of 10% solution
2. There is 2% saline in water
3. The equation is 10% of 1 gallon = 2% of solution of x gallons of water + saline
0.1 = 0.02(x + 1)
Subtracting 0.02 from both sides, we get
0.1 -0.02= 0.02x +0.02 -0.02
0.08 = 0.02x
Dividing both sides by 0.02, we get
0.08/0.02 = 0.02x/0.02
x = 4.
4. The answer is 4 gallons of water.
Hope you will understand the concept.
Thank you.
There is 1 gallon of 10% solution.. There is 0% saline in water.. The equation is (0.1)(1)+0.02(x+1) so therefore answer is 4 gallons
We are given that some water is added to a gallon of 10% saline to create 2% solution.
Let us assume x gallons of water is added in 10% of a gallon of saline.
Therefore,
10% of 1 gallon = 2 % of (solutions of x gallons of water + saline).
0.1 = 0.02 (x+1)
0.1 = 0.02x +0.02
Subtracting 0.02 from both sides, we get
0.1 -0.02= 0.02x +0.02 -0.02
0.08 = 0.02x
Dividing both sides by 0.02, we get
0.08/0.02 = 0.02x/0.02
x = 4.Therefore, 4 gallons of water must be added to a gallon of 10% saline solution to create a 2% solution.
We have 1 gallon of 10% saline.
How much water (x liters of 0% saline) must be added to make a 2% saline solution?
.10 * 1 + 0x = .02 * (1 +x)
.1 = .02 + .02x
.08 = .02x
x = 4 gallons of water must be added
4 gallons of water should be added in 10% saline solution.
Step-by-step explanation:
Let x gallon of water is added in one gallon of 10% saline solution.
Therefore total volume of 10% saline solution will become (1 + x) gallons
Since concentration of water is 0% so equation will be
0.10(1) + 0(x) = .02(1 + x)
0.10 = 0.02(1 + x)
1 + x = [tex]\frac{0.10}{0.02}[/tex]
x + 1 = 5
x = 5 - 1
x = 4 gallons
Therefore, 4 gallons of water should be added to 10% saline solution to create 2% solution.