Use the third pair of points to do each of the following. The third pair is (-6, 7), (-3, -4). 1. Give the slope

2. Write the equation in point-slope form.

3. Write the equation in slope-intercept form.

4. Write the equation of the line in standard form.

5. Give the x-intercept from standard form (remember, let y=0)

6. Give the y-intercept from standard form (remember, let x=0)

Parallel to 2x+y=-5

2x+y-2x=-5-2x

y=-2x-5

y=mx+b

Slope: m=-2

As the line is parallel must have the same slope:

m=-2

And it has an x-intercept of 2: when x=2, y=0→Point: P1=(2,0)=(x1,y1)

x1=2, y1=0

y-y1=m(x-x1)

y-0=(-2)(x-2)

y=-2x+4

In standard form:

y+2x=-2x+2x+4

2x+y=4

The equation of the line, in standard form, that passes through the origin and is parallel to x+y=6 is x+y=0

Paralell to 2x+y=-5

means it has same slope

means it is in form

2x+y=c where we have to find c

convert to slope intercept

minus 2x both sides

xint of 2

xint is where th eline crosses the x axis or where y=0, x=2

2(2)+0=c

2(2)=c

4=c

the equation is 2x+y=4

1. [tex]-5x+3y+44=0[/tex]

2. [tex]2x+y-2=0[/tex]

3. [tex]2x+y-4=0[/tex]

Step-by-step explanation:

Standard form of a line is [tex]Ax+By+C=0[/tex].

If a line passing through two points then the equation of line is

[tex]y-y_1=m(x-x_1)[/tex]

where, m is slope, i.e.,[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex].

1.

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

[tex]y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)[/tex]

[tex]y+3=\dfrac{-5}{-3}(x-7)[/tex]

[tex]y+3=\dfrac{5}{3}(x-7)[/tex]

[tex]3(y+3)=5(x-7)[/tex]

[tex]3y+9=5x-35[/tex]

[tex]-5x+3y+9+35=0[/tex]

[tex]-5x+3y+44=0[/tex]

Therefore, the required equation is [tex]-5x+3y+44=0[/tex].

2.

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to [tex]2 x + y =-5[/tex].

Slope of the line : [tex]m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2[/tex]

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

[tex]y-2=-2(x-0)[/tex]

[tex]y-2=-2x[/tex]

[tex]2x+y-2=0[/tex]

Therefore, the required equation is [tex]2x+y-2=0[/tex].

3.

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to [tex]2x + y =-5[/tex].

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

[tex]y-0=-2(x-2)[/tex]

[tex]y=-2x+4[/tex]

[tex]2x+y-4=0[/tex]

Therefore, the required equation is [tex]2x+y-4=0[/tex].

1. M= -2/32. -1-7= -2/3 (6-6)3. y= -2/3x +3 4. 2x+3y=95. (9/2,0)6. (0,3)

Step-by-step explanation:

Hope this helps! Please consider making me BrainliestIf you need anymore help feel free to ask me. If not then have a wonderful day today!

X+y=0

-2x+y=2

-2x+y=-4

The general equation of the line is ⇒⇒⇒ y = mx + c

where: m is the slope of the line , c is constant

The given line is 2x + y = -5 ⇒⇒⇒ ∴ y = -5 - 2x

The slope of the given line = -2

The required line is parallel to the given line . So, it have the same slope

∴ m = -2

∴ The general equation of the line will be ⇒⇒⇒ y = -2x + c

to find c we need a point on the line

x-intercept of 2 which mean the line pass through (2,0)

substitute with (2,0) to find C

∴ 0 = -2*2 +c ⇒⇒⇒ c = 4

The required line is ⇒⇒⇒⇒ y = -2x + 4

OR 2x + y = 4

Y=2x-5 because parallel means keep the slope the same and the formula is y=mx+b b is y and y is -5 so your answer is y=2x-5

The equation of a line is represented by the affine function y = mx + b, where m represents the slope, b the y-intercept, x and y the coordinates of a point.

First, we need to transform 2x + y = -5 to the y = mx + b form.

First, let's subtract 2x from both sides to have the y on the left side, and all the other variables and numbers on the right side.

2x + y - 2x = -5 - 2x

y = -2x - 5

That's the standard form of the equation. Now we need to find a parallel.

2 parallel lines have the same slope so m = -2. So we get y = -2x + b

By hypothesis, the line have an x-intercept of 2, which means that for y=0, x = 2. Let's insert those coordinates into our equation to find the y-intercept.

y = -2x + b

0 = -2 * 2 + b

0 = -4 + b

Add 4 on both sides to have b on a side and its value on the other

0 + 4 = -4 + 4 + b

4 = b

We found the y-intercept.

So, the equation of the parallel line is y = -2x + 4

I've added a picture of the graphical representation of both lines.

Hope this Helps! 🙂

[tex]Write the equation of the line, in standard form, that has a x-intercept of 2 and is parallel to 2x+[/tex]

1. M= -2/3

2. -1-7= -2/3 (6-6)

3. y= -2/3x +3

4. 2x+3y=9

5. (9/2,0)

6. (0,3)

Step-by-step explanation:

Hope this helps! Please consider making me BrainliestIf you need anymore help feel free to ask me. If not then have a wonderful day today!

To become parallel, equations need to have the same slope for the x-axis. To do that, let's convert the equation to Slope Intercept Form.

2x + y = -5

Subtract y from both sides

2x = -y - 5

Divide both sides by 2.

x = -1/2y - 5/2

The slope is -1/2. Knowing this, we can make this equation.

x = -1/2y + 2

Now, we have to convert that into Standard Form.

x = -1/2y + 2

Add 1/2y to both sides.

x + 1/2y = 2

Multiply everything by 2.

2x + y = 4