# Use the third pair of points to do each of the following. The third pair is (-6, 7), (-3, -4).1. Give

Use the third pair of points to do each of the following. The third pair is (-6, 7), (-3, -4). 1. Give the slope
2. Write the equation in point-slope form.
3. Write the equation in slope-intercept form.
4. Write the equation of the line in standard form.
5. Give the x-intercept from standard form (remember, let y=0)
6. Give the y-intercept from standard form (remember, let x=0)

## This Post Has 10 Comments

1. sarahhope55 says:

Parallel to 2x+y=-5
2x+y-2x=-5-2x
y=-2x-5
y=mx+b
Slope: m=-2

As the line is parallel must have the same slope:
m=-2
And it has an x-intercept of 2: when x=2, y=0→Point: P1=(2,0)=(x1,y1)
x1=2, y1=0

y-y1=m(x-x1)
y-0=(-2)(x-2)
y=-2x+4
In standard form:
y+2x=-2x+2x+4
2x+y=4

The equation of the line, in standard form, that passes through the origin and is parallel to x+y=6 is x+y=0

2. dbethel8408 says:

Paralell to 2x+y=-5
means it has same slope
means it is in form
2x+y=c where we have to find c
convert to slope intercept
minus 2x both sides

xint of 2
xint is where th eline crosses the x axis or where y=0, x=2

2(2)+0=c
2(2)=c
4=c

the equation is 2x+y=4

3. meganxc98 says:

1. $-5x+3y+44=0$

2. $2x+y-2=0$

3. $2x+y-4=0$

Step-by-step explanation:

Standard form of a line is $Ax+By+C=0$.

If a line passing through two points then the equation of line is

$y-y_1=m(x-x_1)$

where, m is slope, i.e.,$m=\dfrac{y_2-y_1}{x_2-x_1}$.

1.

The line passes through the points (7,-3) and (4,-8). So, the equation of line is

$y-(-3)=\dfrac{-8-(-3)}{4-7}(x-7)$

$y+3=\dfrac{-5}{-3}(x-7)$

$y+3=\dfrac{5}{3}(x-7)$

$3(y+3)=5(x-7)$

$3y+9=5x-35$

$-5x+3y+9+35=0$

$-5x+3y+44=0$

Therefore, the required equation is $-5x+3y+44=0$.

2.

We need to find the equation of the line, in standard form, that has a y-intercept of 2 and is parallel to $2 x + y =-5$.

Slope of the line : $m=\dfrac{-\text{Coefficient of x}}{\text{Coefficient of y}}=\dfrac{-2}{1}=-2$

Slope of parallel lines are equal. So, the slope of required line is -2 and it passes through the point (0,2).

Equation of line is

$y-2=-2(x-0)$

$y-2=-2x$

$2x+y-2=0$

Therefore, the required equation is $2x+y-2=0$.

3.

We need to find the equation of the line, in standard form, that has an x-intercept of 2 and is parallel to $2x + y =-5$.

From part 2, the slope of this line is -2. So, slope of required line is -2 and it passes through the point (2,0).

Equation of line is

$y-0=-2(x-2)$

$y=-2x+4$

$2x+y-4=0$

Therefore, the required equation is $2x+y-4=0$.

4. dprajapati832000 says:

1. M= -2/32. -1-7= -2/3 (6-6)3. y= -2/3x +3 4. 2x+3y=95. (9/2,0)6. (0,3)

Step-by-step explanation:

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5. rosemary909 says:

X+y=0
-2x+y=2
-2x+y=-4

6. samgirl2000 says:

The general equation of the line is ⇒⇒⇒ y = mx + c
where: m is the slope of the line ,  c is constant
The given line is 2x + y = -5 ⇒⇒⇒ ∴ y = -5 - 2x
The slope of the given line = -2
The required line is parallel to the given line . So, it have the same slope
∴ m = -2
∴ The general equation of the line will be ⇒⇒⇒ y = -2x + c
to find c we need a point on the line
x-intercept of 2 which mean the line pass through (2,0)

substitute with (2,0) to find C

∴ 0 = -2*2 +c ⇒⇒⇒ c = 4

The required line is ⇒⇒⇒⇒ y = -2x + 4

OR                        2x + y = 4

7. evanwall91 says:

Y=2x-5 because parallel means keep the slope the same and the formula is y=mx+b b is y and y is -5 so your answer is y=2x-5

8. masterdavey3691 says:

The equation of a line is represented by the affine function y = mx + b, where m represents the slope, b the y-intercept, x and y the coordinates of a point.
First, we need to transform 2x + y = -5 to the y = mx + b form.
First, let's subtract 2x from both sides to have the y on the left side, and all the other variables and numbers on the right side.
2x + y - 2x = -5 - 2x
y = -2x - 5
That's the standard form of the equation. Now we need to find a parallel.
2 parallel lines have the same slope so m = -2. So we get y = -2x + b
By hypothesis, the line have an x-intercept of 2, which means that for y=0, x = 2. Let's insert those coordinates into our equation to find the y-intercept.
y = -2x + b
0 = -2 * 2 + b
0 = -4 + b
Add 4 on both sides to have b on a side and its value on the other
0 + 4 = -4 + 4 + b
4 = b
We found the y-intercept.
So, the equation of the parallel line is y = -2x + 4

I've added a picture of the graphical representation of both lines.

Hope this Helps! 🙂

$Write the equation of the line, in standard form, that has a x-intercept of 2 and is parallel to 2x+$

9. leeorareeves299 says:

1. M= -2/3

2. -1-7= -2/3 (6-6)

3. y= -2/3x +3

4. 2x+3y=9

5. (9/2,0)

6. (0,3)

Step-by-step explanation:

Hope this helps! Please consider making me BrainliestIf you need anymore help feel free to ask me. If not then have a wonderful day today!

10. devila321 says:

To become parallel, equations need to have the same slope for the x-axis. To do that, let's convert the equation to Slope Intercept Form.

2x + y = -5
Subtract y from both sides
2x = -y - 5
Divide both sides by 2.
x = -1/2y - 5/2

The slope is -1/2. Knowing this, we can make this equation.

x = -1/2y + 2

Now, we have to convert that into Standard Form.

x = -1/2y + 2