Volume of HCl used 25.0mL 4 lInitial burette reading 0.50mLFinal burette reading 25.60mLConcentration

Volume of HCl used 25.0mL 4 l Initial burette reading 0.50mL
Final burette reading 25.60mL
Concentration of KOH 1.0M
the molarity
HCl solution
Calculate​

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  1. 1.0 M

    Explanation:

    Reaction equation;

    KOH(aq) + HCl(aq) > KCl(aq) + H2O(l)

    Concentration of acid CA = ?

    Concentration of base CB = 1.0 M

    Volume of base VB = 25.60 - 0.50 = 25.1 ml

    Volume of acid VB =  25.0 ml

    Number of moles of acid NA = 1

    Number of moles of base NB =2

    CAVA/CBVB =NA/NB

    CAVANB = CBVBNA

    CA = CBVBNA/VANB

    CA = 1 * 25.1 * 1/25.0 *1

    CA = 1.0 M

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