Volume of HCl used 25.0mL 4 lInitial burette reading 0.50mLFinal burette reading 25.60mLConcentration

Comments (3) on “Volume of HCl used 25.0mL 4 lInitial burette reading 0.50mLFinal burette reading 25.60mLConcentration”

1. You know how the first one if filled up like the objects do the same but with the other categories

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2. i think the answer is terrae but not 100 percent sure. ▓▬▬ §

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3. 1.0 M

   Explanation:

   Reaction equation;

   KOH(aq) + HCl(aq) > KCl(aq) + H2O(l)

   Concentration of acid CA = ?

   Concentration of base CB = 1.0 M

   Volume of base VB = 25.60 - 0.50 = 25.1 ml

   Volume of acid VB =  25.0 ml

   Number of moles of acid NA = 1

   Number of moles of base NB =2

   CAVA/CBVB =NA/NB

   CAVANB = CBVBNA

   CA = CBVBNA/VANB

   CA = 1 * 25.1 * 1/25.0 *1

   CA = 1.0 M

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