What is a point slope equation of the line with slope -13 that goes through the point (5,7)

What is a point slope equation of the line with slope -13 that goes through the point (5,7)

9. Find the area of a circle having a circumference of 382. Round to the nearest tenth. Use 3.14 for 1. a. 1133.5 units b. 1078.6

1. angie249 says:

y - 7 = -13( x-5)

Step-by-step explanation:

The  point slope form of a line is

y-y1 = m(x-x1)

The slope is -13 and the point is (5,7)

y - 7 = -13( x-5)

2. 10033636 says:

It should be A. y-7 = -13(x-5)

3. odetteerivera says:

the answer will mostlikely be D. cause

Step-by-step explanation:

it makes the most sense cause if 5 goes first then it will be the right answer and it as to be subtraction

Final D. y - 5 = - 13(x - 7)

4. chessacs2950 says:

A

Step-by-step explanation:

(x1,y1)=(5,7)

(y-y1)/(x-x1)=slope

(y-7)/(x-5)=-13

y-7=-13(x-5)

6. oliviajewelwilliams says:

A.  $(y-7)=-13(x-5)$

Step-by-step explanation:

We know that the equation of a line having slope m and passing thorough (a,b) in point slope form is given by :-

$(y-b)=m(x-a)$

Given : Slope of a line : m=-13 and point =(5,7)

Similarly, the point slope equation of the line with slope -13 that goes through the point (5,7) is given by :-

$(y-7)=-13(x-5)$

Hello
the point-slope equation of the line with slope -13 that goes through the point (5, 7) is :   A)    y - 7 = -13(x - 5)
because ; 7-7= -13(5-5)

8. fhemmie963 says:

A.  $(y-7)=-13(x-5)$

Step-by-step explanation:

We know that the equation of a line having slope m and passing thorough (a,b) in point slope form is given by :-

$(y-b)=m(x-a)$

Given : Slope of a line : m=-13 and point =(5,7)

Similarly, the point slope equation of the line with slope -13 that goes through the point (5,7) is given by :-

$(y-7)=-13(x-5)$

9. u8p4 says:

Point slope formula:
$y-y_1=m(x-x_1)$

We know that:
m=-13
y1=7
x1=5
Plug those into the equation to get a final answer of:
$y-7=-13(x-5)$