What is the area of the trapezoid with height 10 units? enter your answer in the box.

What is the area of the trapezoid with height 10 units? enter your answer in the box.

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  1. 。☆✼★ ━━━━━━━━━━━━━━  ☾  

    You will need the equation:

    Area = (a+b)/2 x h

    Substitute the values in:

    Area = (5 + 29)/2 x 10

    You will get your answer as:

    Area = 170

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  2. Use Formula A=1/2h(b1+b2)

    Question 1

    What is the area of this trapezoid?  

    Questions 2

    What is the area of the trapezoid with height 10 units?

    Question 3

    What is the area of this trapezoid?

    Question 4

    The figure shows the front side of a metal desk in the shape of a trapezoid.  What is the area of this trapezoid?

    Question 5

    Duc has a trapezoid shaped section of his yard fenced off for his pets.  The lengths of the parallel sides of the trapezoid are 8 ft and 14 ft.  The height of the trapezoid section is 4 ft.

    [tex]What is the area of the trapezoid with height 10 units?[/tex]
    [tex]What is the area of the trapezoid with height 10 units?[/tex]
    [tex]What is the area of the trapezoid with height 10 units?[/tex]
    [tex]What is the area of the trapezoid with height 10 units?[/tex]
    [tex]What is the area of the trapezoid with height 10 units?[/tex]

  3. If by "long leg lengths" you mean the hypotenuse then the area is 116 sq. units.  If you mean the bases of the triangles then the area is 170 sq. units.

    If the length of 12 is the hypotenuse, we first must find the base of the triangles using the Pythagorean theorem:

    10² + b² = 12²
    100 + b² = 144
    b² = 44
    b = √44 = 6.6

    This means we have two triangles and a rectangle.  The area of the rectangle is 5(10) = 50 sq. units.  The area of each triangle is 1/2(6.6)(10) = 33.  Adding all 3 together we have:

    50+33+33 = 116 sq. units.

    If the 12 is the base, then we have the rectangle with the area of 5(10) = 50 and two triangles each with an area of 1/2(12)(10) = 60:

    50+60+60 = 170 sq. units.

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