Home Mathematics What is the difference of 3 49 and 2 59? Select one: A. 89 B. 1 19 C. 1 23 D. 2 49 What is the difference of 3 49 and 2 59? Select one: A. 89 B. 1 19 C. 1 23 D. 2 49Mathematics ChanclerOctober 22, 20215 CommentsWhat is the difference of 3 49 and 2 59? Select one: A. 89 B. 1 19 C. 1 23 D. 2 49
A. 2.65Step-by-step explanation:Let mu1 be the mean number of cars that one employee is involved in Detroit plant per dayAnd mu2 be the mean number of cars that one employee is involved in Mexico City plant per dayNull and alternative hypotheses are:[tex]H_{0}[/tex]: mu1-mu2=0[tex]H_{a}[/tex]: mu1-mu2>0This is one tailed t test and one tailed test statistic is given as 2.650.Reply
Answer and Step-by-step explanation:a. Yes, since the highest standard deviation (s4 = 44.51) is significantly more than double the lowest (s3 = 20.83) is plausible.hence, the second option is correct(b) The testing of relevant hypothesis using the output is shown below:As we see thatThe 0.05 is more than the F test P-value i.e 0.0000 So ultimately P-value is lessTherefore we have to reject the null hypothesisSince p-value is less than 0.05 so we reject the null hypothesis. Therefore, the third option is correct(c) The construction is shown below: Since the sample size is the same so for Tuley's HSD it would also same i.e for each pairNow Tuley's HSD is [tex]HSD=4.10\cdot \sqrt{\frac{1049}{7}}=50.19[/tex]The table that reflects the difference in means in different level is as follows Levels Difference in mean4-6 34.854-8 41.924-10 74.154-12 103.966-8 7.076-10 39.36-12 69.118-10 32.238-12 62.0410-12 29.81Now the table of significant difference is Levels Difference in mean4-10 74.154-12 103.966-12 69.118-12 62.04Reply
The answer is 90 which is none of these
Ibelieve the answer is c
A. 2.65
Step-by-step explanation:
Let mu1 be the mean number of cars that one employee is involved in Detroit plant per day
And mu2 be the mean number of cars that one employee is involved in Mexico City plant per day
Null and alternative hypotheses are:
[tex]H_{0}[/tex]: mu1-mu2=0[tex]H_{a}[/tex]: mu1-mu2>0
This is one tailed t test and one tailed test statistic is given as 2.650.
Answer and Step-by-step explanation:
a. Yes, since the highest standard deviation (s4 = 44.51) is significantly more than double the lowest (s3 = 20.83) is plausible.
hence, the second option is correct
(b) The testing of relevant hypothesis using the output is shown below:
As we see that
The 0.05 is more than the F test P-value i.e 0.0000
So ultimately P-value is less
Therefore we have to reject the null hypothesis
Since p-value is less than 0.05 so we reject the null hypothesis.
Therefore, the third option is correct
(c) The construction is shown below:
Since the sample size is the same so for Tuley's HSD it would also same i.e for each pair
Now Tuley's HSD is
[tex]HSD=4.10\cdot \sqrt{\frac{1049}{7}}=50.19[/tex]
The table that reflects the difference in means in different level is as follows
Levels Difference in mean
4-6 34.85
4-8 41.92
4-10 74.15
4-12 103.96
6-8 7.07
6-10 39.3
6-12 69.11
8-10 32.23
8-12 62.04
10-12 29.81
Now the table of significant difference is
Levels Difference in mean
4-10 74.15
4-12 103.96
6-12 69.11
8-12 62.04
A: 0.26 would be the answer