Home History What is the equation in point-slope form for the line parallel to y= -2x + 10 that contains (6,8)? What is the equation in point-slope form for the line parallel to y= -2x + 10 that contains (6,8)?History OofersonOctober 22, 20212 CommentsWhat is the equation in point-slope form for the line parallel to y= -2x + 10 that contains (6,8)?
Hello mate!A linear equation has the form y = ax + bwhere x is the variable, a is the slope and b is the x-intercept.We want to find the pararel line to y = -2x + 10A paralel line of this, will be another line with the same slope ( -2 in this case) and a different x-intercept; then our line has the shape of:y = -2x + band we know that this line pases through the point (6,8), and with this info we could find the value of b:8 = -2*6 + bb = 8 + 12 = 20then y = -2x + 20 is the pararel line that passes through the point (6.8)Then the correct answer is the option a:a) y - 8 = -2(x - 6) = -2x + 12y = -2x + 12 + 8 = -2x + 20Reply
In the equation y=mx+b
m = slope
b = y-intercept
x = variable
y = what you get
Hello mate!
A linear equation has the form y = ax + b
where x is the variable, a is the slope and b is the x-intercept.
We want to find the pararel line to y = -2x + 10
A paralel line of this, will be another line with the same slope ( -2 in this case) and a different x-intercept; then our line has the shape of:
y = -2x + b
and we know that this line pases through the point (6,8), and with this info we could find the value of b:
8 = -2*6 + b
b = 8 + 12 = 20
then y = -2x + 20 is the pararel line that passes through the point (6.8)
Then the correct answer is the option a:
a) y - 8 = -2(x - 6) = -2x + 12
y = -2x + 12 + 8 = -2x + 20