Comments (10) on “What is the equation of the line that passes through the point (−3,4) and has a slope of 1 ?”

  2. y = x + 7

    Step-by-step explanation:

    The equation of a line in slope- intercept form is

    y = mx + c ( m is the slope and c the y- intercept )

    Here m = 1, thus

    y = x + c ← is the partial equation

    To find c substitute (- 3, 4) into the partial equation

    4 = - 3 + c ⇒ c = 4 + 3 = 7

    y = x + 7 ← equation of line

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  3. y = 1/3 x + 5

    Step-by-step explanation:

    y = mx + b   m: slope     b: y intercept

    for line passing point (-3 , 4)

    b = y - mx = 4 - (1/3) x (-3) = 4 + 1 = 5

    equation: y = 1/3 x + 5

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  6. ♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

    We have following equation to find the point-slope form of the linear functions.

    [tex]y - y(0) = m \times ( \: x - x(0) \:)[/tex]

    In which :

    [tex]y(0) = y \: \: given \: \: point = 4[/tex]

    [tex]x(0) = x \: \: given \: \: point = - 3[/tex]

    [tex]m = slope = 1[/tex]

    Now just need to put the coordinates and the slope in the above equation.

    [tex]y - 4 = 1 \times ( \: x - ( - 3) \: )[/tex]

    [tex]y - 4 = x + 3[/tex]

    Add sides 4

    [tex]y - 4 + 4 = x + 3 + 4[/tex]

    [tex]y = x + 7[/tex]

    Done...

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  7. [tex]y=x+7[/tex]

    Step-by-step explanation:

    We can use the equation y=mx+b to solve this problem.

    First, we know the 'm' or slope of the line, so we'll substitute that into the equation.

    [tex]y=mx+b\\y=1x+b\\y=x+b[/tex]

    Now, let's solve for b. We already have x and y values - x= -3 and y=4. Let's substitute that into y=x+b and solve.

    [tex]y=x+b\\4=-3+b\\b=4+3\\b=7[/tex]

    Finally, let's plug the slope and y intercept ('b') back into y=mx+b.

    [tex]y=mx+b\\y=(1)x+(7)\\y=x+7[/tex]

    That's the answer to this problem.

    I hope this helps.

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