What is the following quotient? 6-3

3(26

20

O

2(13)-V18

2(V)-3(12)

3(1/3)-V18

3(1/3)-3(2)

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What is the following quotient? 6-3

3(26

20

O

2(13)-V18

2(V)-3(12)

3(1/3)-V18

3(1/3)-3(2)

Question 1

24/6 yields 4 while 54/6 yields 9. every other combination of numbers will yield at least one result with a quotient and remainder.

Question 2

8 is the only number that is a common factor of 24, 48 and 144

Question 3

- (y^4)^2 = y^(4*2) = y^8

- (y^5)^2 = y^(5*2) = y^10

- (y^10)^2 = y^(10*2) = y^20 (correct answer)

- (y^12)^2 = y^(12*2) = y^24

Question 4

64^8 = 2^48

- (8^4)^2 = (8^8) = (2^3)^8 = (2^24)

- (32^4)^2 = (32^8) = (2^5)^8 = (2^40)

- (32^8)^2 = (32^16) = (2^5)^16 = (2^80)

- (8^8)^2 = (8^16) = (2^3)^16 = (2^48) (correct answer)

Question 5

4 * 12 = 48

-2 * -24 = 48

-8 * 6 = -48 (correct answer)

6 * 8 = 48

Question 6

131 is the only prime number

Question 7

104 = 2 * 2 * 2 * 13 = 2^3 * 13

Question 8

476 = 2 * 2 * 7 * 17 = 2^2 * 7 * 17

Question 9

104 = 2 * 2 * 2 * 13

260 = 2 * 2 * 5 * 13

Greatest common factor = 2 * 2 * 13 = 52

Question 10

312 = 2 * 2 * 3 * 13

444 = 2 * 2 * 3 * 37

Greatest common factor = 2 * 2 * 3 = 12

Question 11

a^6/a^2 = a^4 i.e. a to the power of 4

Question 12

Power of a Power Property

Question 13

(h/5)^2 = (h^2)/(5^2) = (h^2)/25

fraction numerator h squared over denominator 25 end fraction

Question 14

(3* m^2 * n^4)^3 = 3^3 * m^2*3 * n^4*3 = 27 * m^6 * n^12

27 m to the power of 6 end exponent n to the power of 12

Question 15

(3y)^4 * y^(-2) = 3 * y^(4-2) = 3y^2

3 y squared

Question 16 is missing

Question 17

(4 * x^8) / (16 * x^2) = x^(8-2) / 4 = (x^6)/4

1. 5/16

2. 1/3

3. 3/91

4. 2 and 3/61

5. 7/64

Step-by-step explanation:

For I think all of these problems, I used KCF, you might know this already but, it's Keep, Change, Flip.

1. m ÷ n, place your values into the variables.

1/4 ÷ 4/5 We keep 1/4 the same, change ÷ to multiplication and flip 4/5 to 5/4

1/4 * 5/4 = multiply across. 5/16 we can't simplify.

2. 2/9 ÷ 4/6 = 2/9 * 6/4 = 12/36 and simplify that to 1/3. 12 can go into 36 three times.

3. For this, we need to get the variable r by itself. And to do that we do reverse order of operations. 13r is multiplication, so we divide both sides by 13 to get r by itself.

13r = 3/7 would be r= 3/91

4. We have to turn each fraction into a mixed number.

6 1/4 would equal 25/4 because we times 4 by 6, 24, and add the one, 25.

3 1/20 would equal 61/20

25/4 ÷ 61/20 = 500/4 = 125/61 = 2 and 3/61

5. We can put 8 over 1, 8/1

7/8 ÷ 8/1 then Keep, change, flip

7/8 * 1/8 multiply across

7/64

B is le answer

Step-by-step explanation:

your answer is -9

step-by-step explanation:

answer: i literally just answered this question but they want me to do it again

step-by-step explanation:

B because it is the answer

The answer is 5=x+1/5

24 and 54

8

y to the power 5

negative 8 and 6

131

2 squared times 13

C

Um I'm late but its not any of the others so

n/2-3=13;n=32

Step-by-step explanation: the equation and solution correctly represents this sentence is n/2-3=13;n=32,

first we have to keep in mind the beginning of the exercise which is (three less) then we know that the 3 has a sign of subtraction(-3), when we meet this, we can know that this exercise has only two possible good answer.

Only the equations which have a (-3) inside will be good,the rest of equation has a 3 with a sum sign

N/2+3=13;n=5 ,

n/2+3=13;=20

then we can omit the past equations, and this let us this equations as possible.

n/2-3=13;n=32

n/2-3=13;n=8

after this we only need resolve the equation to get a correct result, only the equation with a correct result will be the correct answer,

then we proceed to clear n from each equation.

for this equation the result must be equal to 8 if we clear n.

n/2-3=13;n=8

n/2-3=13

we pass the three to the other side with sum sign

n/2=13 + 3

we resolve the sum

n/2=16

after we pass the 2 multiplying to the other side

n = 16 × 2

we resolve the product of the multiplication

n = 32

but this answer said the result must be equal to 8

n=8 ≠ n = 32

as this result is different, we can conclude that this is a bad answer,

the we get only one possibility

this equation

n/2-3=13;n=32

for this equation the result must be equal to 32 if we clear n.

n/2-3=13;n=8

n/2-3=13

we pass the three to the other side with sum sign

n/2=13 + 3

we resolve the sum

n/2=16

after we pass the 2 multiplying to the other side

n = 16 × 2

we resolve the product of the multiplication

n = 32