# What is the magnitude of the dipole moment formed by separating a proton and an electron by 100 pm

What is the magnitude of the dipole moment formed by separating a proton and an electron by 100 pm

## This Post Has 3 Comments

1. owenr4758 says:

When two electrical charges, of opposite sign and equal magnitude, are separated by a distance, a dipole is established. The size of a dipole is measured by its dipole moment . Dipole moment is measured in Debye units, which is equal to the distance between the charges multiplied by the charge

Dipolemoment 'D' = e x d where e= charge and d= distance by which charge is separated.
In this case e = charge on electron = 1.6 x10^-19 C

D = 1.6 x10^-19 C ( 1x10^-10 m) =1.6x10^-29 Cm

2. david7962 says:

p=q x D = 1.6 x 10^- 19x85x 10^-12 = 3.7 D

3. AeelynRamos says:

dipole moment is defined as product of charge and distance between between.

$P = qd$

$q = 1.6 \times 10^{-19} C$

$d = 80 pm = 80 \times 10^{-12} m$

$P = (1.6 \times 10^{-19})(80 \times 10^{-12})$

$P = 1.28 \times 10^{-29} Cm$

so above is the dipole moment of the given charges