What is the magnitude of the dipole moment formed by separating a proton and an electron by 100 pm

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What is the magnitude of the dipole moment formed by separating a proton and an electron by 100 pm

When two electrical charges, of opposite sign and equal magnitude, are separated by a distance, a dipole is established. The size of a dipole is measured by its dipole moment . Dipole moment is measured in Debye units, which is equal to the distance between the charges multiplied by the charge

Dipolemoment 'D' = e x d where e= charge and d= distance by which charge is separated.

In this case e = charge on electron = 1.6 x10^-19 C

D = 1.6 x10^-19 C ( 1x10^-10 m) =1.6x10^-29 Cm

p=q x D = 1.6 x 10^- 19x85x 10^-12 = 3.7 D

dipole moment is defined as product of charge and distance between between.

[tex]P = qd[/tex]

[tex]q = 1.6 \times 10^{-19} C[/tex]

[tex]d = 80 pm = 80 \times 10^{-12} m[/tex]

[tex]P = (1.6 \times 10^{-19})(80 \times 10^{-12})[/tex]

[tex]P = 1.28 \times 10^{-29} Cm[/tex]

so above is the dipole moment of the given charges