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  1. Attached solution and work.
    [tex]The coordinates of 3 of the vertices of a parallelogram are (–3, 4), (–2, 1), and (2, 6). what is th[/tex]

  2. To simplify the discussion, we will only consider two-class classifiers in this section and define a linear classifier as a two-class classifier that decides class membership by comparing a linear combination of the features to a threshold.

    Figure 14.8: There are an infinite number of hyperplanes that separate two linearly separable classes.

    \includegraphics[width=6cm]{vclassline.eps}

    In two dimensions, a linear classifier is a line. Five examples are shown in Figure 14.8 . These lines have the functional form $w_1x_1+w_2x_2=b$. The classification rule of a linear classifier is to assign a document to $c$ if $w_1x_1+w_2x_2>b$ and to $\overline{c}$ if $w_1x_1+w_2x_2\leq b$. Here, $(x_1, x_2)^{T}$ is the two-dimensional vector representation of the document and $(w_1, w_2)^{T}$ is the parameter vector that defines (together with $b$) the decision boundary. An alternative geometric interpretation of a linear classifier is provided in Figure 15.7 (page [*]).

    We can generalize this 2D linear classifier to higher dimensions by defining a hyperplane as we did in Equation 140, repeated here as Equation 144:

    \begin{displaymath}

    \vec{w}^{T}\vec{x} = b

    \end{displaymath}(144)

    The assignment criterion then is: assign to $c$ if $\vec{w}^{T}\vec{x} > b$ and to $\overline{c}$ if $\vec{w}^{T}\vec{x} \leq b$. We call a hyperplane that we use as a linear classifier a decision hyperplane .

    Figure 14.9: Linear classification algorithm.

    \begin{figure}\begin{algorithm}{ApplyLinearClassifier}{\vec{w},b,\vec{x}}

    score ...

    ...in{IF}{score>b}

    \RETURN{1}

    \ELSE

    \RETURN{0}

    \end{IF}\end{algorithm}

    \end{figure}

    The corresponding algorithm for linear classification in $M$ dimensions is shown in Figure 14.9 . Linear classification at first seems trivial given the simplicity of this algorithm. However, the difficulty is in training the linear classifier, that is, in determining the parameters $\vec{w}$ and $b$ based on the training set.

    Explanation:

  3. The opposite of -2.5 would 2.5.

    Step-by-step explanation:

    Positive 2.5. I know it's not any of the answer choices you listed but the opposite of a negative is a positive. I really hope I helped you.

  4. -2.5 and 2.5 compare to eachother on the number line because they are the exact same distance away from 0.

    Step-by-step explanation:

    0 is in the very middle and to get -2.5 you go to the left 2.5 paces but to get to +2.5 you go to the right 2.5 paces. Either way you have to move Exactly 2.5 paces either to the left or right depending on if you want a positive or negative.

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