To find the probability the contestant is doing a Conky, the formula is : P = Number of favored outcome / Total number of outcome. The number of favored outcome is 1, the Conky. The total number of outcome is 4 which is the total number of dance moves.
P = 1 / 4 = 0.25
Therefore, there is a 25% probability that the contestant is doing a Conky.
Each eukaryotic cell has a plasma membrane, cytoplasm, a nucleus, ribosomes, mitochondria, peroxisomes, and in some, vacuoles; however, there are some striking differences between animal and plant cells.
[tex]\bold{\dfrac{1}{36}}[/tex]
Step-by-step explanation:
The first die can be any number: [tex]P = (\dfrac{6}{6}) = 1[/tex]
The second die must match the first die: [tex]P = \dfrac{1}{6}[/tex]
The third die must also match the first die: [tex]P = \dfrac{1}{6}[/tex]
1st die and 2nd die and 3rd die = Probability of success
1 x [tex]\dfrac{1}{6}[/tex] x [tex]\dfrac{1}{6}[/tex] = [tex]\dfrac{1}{36}[/tex]
To find the probability the contestant is doing a Conky, the formula is :
P = Number of favored outcome / Total number of outcome. The number of favored outcome is 1, the Conky. The total number of outcome is 4 which is the total number of dance moves.
P = 1 / 4
= 0.25
Therefore, there is a 25% probability that the contestant is doing a Conky.
Ineed the problem dude
Each eukaryotic cell has a plasma membrane, cytoplasm, a nucleus, ribosomes, mitochondria, peroxisomes, and in some, vacuoles; however, there are some striking differences between animal and plant cells.
2/3 , or C is the correct answer! (On e2020 at least)
Hope I helped!
The question to your problem is $10