What is the product of -2x^3+x-5 and x^3-3x-4?(a) show your work(b) is the product of -2x^3 +x-5 and x^3-3x-4 equal to the product of x^3 -3x-4 and

October 22, 2021 Allstar976 6 Comments

What is the product of -2x^3+x-5 and x^3-3x-4? (a) show your work
(b) is the product of -2x^3 +x-5 and x^3-3x-4 equal to the product of x^3 -3x-4 and -2x^3 +x-5? Explain your answer

Mathematics

Comments (6) on “What is the product of -2x^3+x-5 and x^3-3x-4?(a) show your work(b) is the product of -2x^3 +x-5 and x^3-3x-4 equal to the product of x^3 -3x-4 and”

nsald6973 says:
October 23, 2021 at 8:17 am
FULL ANSWERS WITH STEPS
(a) Finding the product of $-2x^{3}+x-5$ and $x^{3}-3x-4$
$(-2x^{3}+x-5)(x^{3}-3x-4)$
$=-2x^{3}(x^{3}-3x-4)+x(x^{3}-3x-4)-5(x^{3}-3x-4)$
$=-2x^{3}*x^{3}-2x^{3}*(-3x)-2x^{3}*(-4)+x*x^{3}+x*(-3x)+x*(-4)-5*x^{3}-5*(-3x)-5*(-4)$
$=-2x^{6}+6x^{4}+8x^{3}+x^{4}-3x^{2}-4x-5x^{3}+15x+20$
$=-2x^{6}+6x^{4}+x^{4}+8x^{3}-5x^{3}-3x^{2}-4x+15x+20$
$=-2x^{6}+7x^{4}+3x^{3}-3x^{2}+11x+20$
(b)
1)Finding the product of $-2x^{3}+x-5$ and $x^{3}-3x-4$
$(-2x^{3}+x-5)(x^{3}-3x-4)$
$=-2x^{3}(x^{3}-3x-4)+x(x^{3}-3x-4)-5(x^{3}-3x-4)$
$=-2x^{3}*x^{3}-2x^{3}*(-3x)-2x^{3}*(-4)+x*x^{3}+x*(-3x)+x*(-4)-5*x^{3}-5*(-3x)-5*(-4)$
$=-2x^{6}+6x^{4}+8x^{3}+x^{4}-3x^{2}-4x-5x^{3}+15x+20$
$=-2x^{6}+6x^{4}+x^{4}+8x^{3}-5x^{3}-3x^{2}-4x+15x+20$
$=-2x^{6}+7x^{4}+3x^{3}-3x^{2}+11x+20$
∴ $(-2x^{3}+x-5)(x^{3}-3x-4)=-2x^{6}+7x^{4}+3x^{3}-3x^{2}+11x+20$ ...(1)
2) Finding the product of $x^{3}-3x-4$ and $-2x^{3}+x-5$
$(x^{3}-3x-4)(-2x^{3}+x-5)$
$=(-2x^{3}+x-5)(x^{3}-3x-4)$
$=-2x^{6}+7x^{4}+3x^{3}-3x^{2}+11x+20$
∴ $(x^{3}-3x-4)(-2x^{3}+x-5)=-2x^{6}+7x^{4}+3x^{3}-3x^{2}+11x+20$ ...(2) [Using (1)]
Now,
$(-2x^{3}+x-5)(x^{3}-3x-4)=(-2x^{3}+x-5)(x^{3}-3x-4)$
⇒ $(-2x^{3}+x-5)(x^{3}-3x-4)=-2x^{6}+7x^{4}+3x^{3}-3x^{2}+11x+20$ [Using (1)]
⇒ $(-2x^{3}+x-5)(x^{3}-3x-4)=(x^{3}-3x-4)(-2x^{3}+x-5)$ [Using (2)]
∴ Product of $-2x^{3}+x-5$ and $x^{3}-3x-4$ = Product of $x^{3}-3x-4$ and $-2x^{3}+x-5$
Hope these may help you.
If you have any doubt, then you can ask me in the comments.
Reply
lllizzas says:
October 23, 2021 at 10:09 am
Answer is in a ph[tex]^{}[/tex]oto. I can't attach it he[tex]^{}[/tex]re, but I uploaded it to a fi[tex]^{}[/tex]le hosting. link below! Good Luck!
bit.[tex]^{}[/tex]ly/3a8Nt8n
Reply
Expert says:
October 23, 2021 at 4:05 pm
both equations and proportions are better.
Reply
bks53 says:
October 23, 2021 at 5:34 pm
-2x³+ x-5x³-3x-4
Collect like terms by calculating the sum or difference of their coefficients.
-2x³-5x³ ---> -2-5x³
Calculate the sum or difference.
-7x³
x-3x
If a term doesn't have a coefficient, it is considered that the coefficient is 1.
1x-3x
Collect like terms by subtracting their coefficients.
1-3x
Calculate sum or difference.
-2x
Final answer.
-7x³+-2x-4
No, the products are not equal because the product of the second equation is 9x³-3x+x-5.
Reply
Expert says:
October 24, 2021 at 1:46 am
answer: download photomath it's legit.
step-by-step explanation:
[tex]Part 2: use the trigonometric ratios 30° and 60° to calculate and label the remaining sides of a bd[/tex]
Reply
randallmatthew5665 says:
October 24, 2021 at 5:00 am
FULL ANSWERS WITH STEPS
(a) Finding the product of $-2x^{3}+x-5$ and $x^{3}-3x-4$
$(-2x^{3}+x-5)(x^{3}-3x-4)$
$=-2x^{3}(x^{3}-3x-4)+x(x^{3}-3x-4)-5(x^{3}-3x-4)$
$=-2x^{3}*x^{3}-2x^{3}*(-3x)-2x^{3}*(-4)+x*x^{3}+x*(-3x)+x*(-4)-5*x^{3}-5*(-3x)-5*(-4)$
$=-2x^{6}+6x^{4}+8x^{3}+x^{4}-3x^{2}-4x-5x^{3}+15x+20$
$=-2x^{6}+6x^{4}+x^{4}+8x^{3}-5x^{3}-3x^{2}-4x+15x+20$
$=-2x^{6}+7x^{4}+3x^{3}-3x^{2}+11x+20$
(b)
1)Finding the product of $-2x^{3}+x-5$ and $x^{3}-3x-4$
$(-2x^{3}+x-5)(x^{3}-3x-4)$
$=-2x^{3}(x^{3}-3x-4)+x(x^{3}-3x-4)-5(x^{3}-3x-4)$
$=-2x^{3}*x^{3}-2x^{3}*(-3x)-2x^{3}*(-4)+x*x^{3}+x*(-3x)+x*(-4)-5*x^{3}-5*(-3x)-5*(-4)$
$=-2x^{6}+6x^{4}+8x^{3}+x^{4}-3x^{2}-4x-5x^{3}+15x+20$
$=-2x^{6}+6x^{4}+x^{4}+8x^{3}-5x^{3}-3x^{2}-4x+15x+20$
$=-2x^{6}+7x^{4}+3x^{3}-3x^{2}+11x+20$
∴ $(-2x^{3}+x-5)(x^{3}-3x-4)=-2x^{6}+7x^{4}+3x^{3}-3x^{2}+11x+20$ ...(1)
2) Finding the product of $x^{3}-3x-4$ and $-2x^{3}+x-5$
$(x^{3}-3x-4)(-2x^{3}+x-5)$
$=(-2x^{3}+x-5)(x^{3}-3x-4)$
$=-2x^{6}+7x^{4}+3x^{3}-3x^{2}+11x+20$
∴ $(x^{3}-3x-4)(-2x^{3}+x-5)=-2x^{6}+7x^{4}+3x^{3}-3x^{2}+11x+20$ ...(2) [Using (1)]
Now,
$(-2x^{3}+x-5)(x^{3}-3x-4)=(-2x^{3}+x-5)(x^{3}-3x-4)$
⇒ $(-2x^{3}+x-5)(x^{3}-3x-4)=-2x^{6}+7x^{4}+3x^{3}-3x^{2}+11x+20$ [Using (1)]
⇒ $(-2x^{3}+x-5)(x^{3}-3x-4)=(x^{3}-3x-4)(-2x^{3}+x-5)$ [Using (2)]
∴ Product of $-2x^{3}+x-5$ and $x^{3}-3x-4$ = Product of $x^{3}-3x-4$ and $-2x^{3}+x-5$
Hope these may help you.
If you have any doubt, then you can ask me in the comments.
Reply

Comments (6) on “What is the product of -2x^3+x-5 and x^3-3x-4?(a) show your work(b) is the product of -2x^3 +x-5 and x^3-3x-4 equal to the product of x^3 -3x-4 and”

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