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  1. We can use the points (14, 20) and (-6, 15) to solve.

    Slope formula: y2-y1/x2-x1

    = 15-20/-6-14

    = -5/-20

    = 1/4

    Hope This helped! Good Luck!

  2. Slope formula: m = [tex]\frac{(y2-y1)}{(x2-x1)}[/tex] (Knowing that m represents the slope)

    Substitute (1,0) for (x1,y1), and (-1,-3) for (x2,y2)

    Slope of the line of (1,0) and (-1,-3) is:

    m = [tex]\frac{(-3-0)}{(-1-1)}[/tex] = [tex]\frac{-3}{-2}[/tex] = [tex]\frac{3}{2}[/tex]  

    (Simplify)

    Slope of the line of (1,0) and (-1,-3) is [tex]\frac{3}{2}[/tex]

  3. Hello! 🙂

    Step-by-step explanation:

    [tex]Slope=\frac{y_2-y_1}{x_2-x_1}[/tex]

    [tex]\frac{8-0}{3-1}=\frac{8}{2}=4[/tex]

    Slope is 4, which is our final answer.

    Hope this helps!

    Thanks!

    Have a nice day! 🙂

    😀

    -Charlie

  4. 4 is the slope because the formula for slope is (y2-y1) / (x2-x1) or (8-0) / (3-1) which simplifies to 8/2 = 4

  5. The slope is [tex]4[/tex]

    Step-by-step explanation:

    The following formula is used to find the slope of a line:

    [tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

    You know that that line passes through these points:

    [tex](1,0)\ and\ (3,8)[/tex]

    Then you can identify that:

    [tex]y_2=0\\y_1=8\\\\x_2=1\\x_1=3[/tex]

    Knowing these values you can substiute them into the formula  [tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]  and evaluate, in order to find the slope of this line.

    This is:

     [tex]m=\frac{0-8}{1-3}\\\\m=\frac{-8}{-2}\\\\m=4[/tex]

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