Home Mathematics What is the solution set of the quadratic equation – 2(2x-7)^2 = – 8 What is the solution set of the quadratic equation – 2(2x-7)^2 = – 8Mathematics mobeteOctober 23, 20213 CommentsWhat is the solution set of the quadratic equation - 2(2x-7)^2 = - 8
see explanationStep-by-step explanation:Given- 2(2x - 7)² = - 8 ( divide both sides by - 2 )(2x - 7)² = 4 ( take the square root of both sides )2x - 7 = ± [tex]\sqrt{4}[/tex] = ± 2 ( add 7 to both sides )2x = 7 ± 22x = 7 - 2 = 5 or 2x = 7 + 2 = 9 ( divide both sides by 2 )x = [tex]\frac{5}{2}[/tex]x = [tex]\frac{9}{2}[/tex]Reply
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step-by-step explanation:
see explanation
Step-by-step explanation:
Given
- 2(2x - 7)² = - 8 ( divide both sides by - 2 )
(2x - 7)² = 4 ( take the square root of both sides )
2x - 7 = ± [tex]\sqrt{4}[/tex] = ± 2 ( add 7 to both sides )
2x = 7 ± 2
2x = 7 - 2 = 5 or 2x = 7 + 2 = 9 ( divide both sides by 2 )
x = [tex]\frac{5}{2}[/tex]
x = [tex]\frac{9}{2}[/tex]
3: 2
step-by-step explanation:
shorter piece is 2: 3, so just reverse it, and you get 3: 2