What is the solution set of the quadratic equation - 2(2x-7)^2 = - 8

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What is the solution set of the quadratic equation - 2(2x-7)^2 = - 8

i can you with this question sweetie!

step-by-step explanation:

see explanation

Step-by-step explanation:

Given

- 2(2x - 7)² = - 8 ( divide both sides by - 2 )

(2x - 7)² = 4 ( take the square root of both sides )

2x - 7 = ± [tex]\sqrt{4}[/tex] = ± 2 ( add 7 to both sides )

2x = 7 ± 2

2x = 7 - 2 = 5 or 2x = 7 + 2 = 9 ( divide both sides by 2 )

x = [tex]\frac{5}{2}[/tex]

x = [tex]\frac{9}{2}[/tex]

3: 2

step-by-step explanation:

shorter piece is 2: 3, so just reverse it, and you get 3: 2