What is the solution set of the quadratic equation – 2(2x-7)^2 = – 8​​

What is the solution set of the quadratic equation - 2(2x-7)^2 = - 8​

Related Posts

This Post Has 3 Comments

  1. see explanation

    Step-by-step explanation:

    Given

    - 2(2x - 7)² = - 8 ( divide both sides by - 2 )

    (2x - 7)² = 4 ( take the square root of both sides )

    2x - 7 = ± [tex]\sqrt{4}[/tex] = ± 2 ( add 7 to both sides )

    2x = 7 ± 2

    2x = 7 - 2 = 5 or 2x = 7 + 2 = 9 ( divide both sides by 2 )

    x = [tex]\frac{5}{2}[/tex]

    x = [tex]\frac{9}{2}[/tex]

Leave a Reply

Your email address will not be published. Required fields are marked *