What is the value of the x variable in the solution to the following system of equations? 4x − 3y = 3 5x − 4y = 3 (5

What is the value of the x variable in the solution to the following system of equations?

4x − 3y = 3
5x − 4y = 3 (5 points)

x can be any number as there are infinitely many solutions to this system
there is no x value as there is no solution to this system
−3
3

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  1. 4x - 3y = 3...multiply by 4
    5x - 4y = 3...multiply by -3

    16x - 12y = 12 (result of multiplying by 4)
    -15x + 12y = - 9 (result of multiplying by -3)
    add
    x = 3

    4x - 3y = 3
    4(3) - 3y = 3
    12 - 3y = 3
    -3y = 3 - 12
    -3y = - 9
    y = -9/-3
    y = 3

    solution is (3,3)and the x = 3

  2.  The required value of variable x is 3.

    Step-by-step explanation:  We are given to find the value of the variable x in the solution to the following system of equations :

    [tex]4x-3y=3~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\5x-4y=3~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)[/tex]

    In order to find the value of x, we need to eliminate y from both the equations.

    Multiplying equation (i) by 4 and equation (ii) by 3, we have

    [tex]4(4x-3y)=4\times 3\\\\\Rightarrow 16x-12y=12~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)\\\\\\3(5x-4y)=3\times3\\\\\Rightarrow 15x-12y=9~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iv)[/tex]

    Subtracting equation (iv) from equation (iii), we get

    [tex](16x-12y)-(15x-12y)=12-9\\\\\Rightarrow x=3.[/tex]

    Thus, the required value of variable x is 3.

  3. Since boh equal 3, set each to each other
    4x-3y=5x-4y
    minus 4x both sides
    -3y=x-4y
    add 4y to both sides
    y=x
    now sub that
    4x-3y=3
    4x-3x=3
    x=3
    x=y
    y=3

    x=3=y

    the solution is (3,3)

  4. There is no x value as there is no solution. I plugged into desmos cause it didnt make sense at first then it showed me that it has no solution. 

  5. I hope this helps you
    [tex]What is the value of the x variable in the solution to the following system of equations? 4x − 3y =[/tex]

  6. We multiply both equations by a constant term so that when we subtract the equations, the y values cancel out:

    4(4x - 3y = 3)
    3(5x - 4y = 3)

    16x - 12y = 12
    15x -12y = 9; subtracting the second equation from the first:

    x = 3

  7. hello : 
    4x − 3y = 3  ...(1)
    5x − 4y = 3   ...(2)
    by (1) : 3y = 4x-3
    y = (4/3)x -1 ...(*)
    by (2) : 4y = 5x-3 
    y = (5/4)x -3/4 ... (**) 
    by (*) (**) ;
    (4/3)x -1  =(5/4)x -3/4 
    (4/3)x-(5/4)x=1-3/4
    (16x-15x)/12 =1/4 = 3/12
    x=3

  8. Solve 4x − 3y = 3 and  5x − 4y = 3

    Step 1: Solve for x in 4x-3y=3:
    4x-3y=3
    4x-3y+3y=3+3y [Add 3y to both sides]
    4x=3y+3
    [tex]\frac{4x}{4} = \frac{3x+3}{4}[/tex] [Divide both sides by 4]
    x=[tex]\frac{3}{4}y+ \frac{3}{4}[/tex]

    Step 2: Substitute [tex]\frac{3}{4}y+ \frac{3}{4}[/tex] for x in 5x-4y=3
    5x-4y=3
    5([tex]\frac{3}{4}y+ \frac{3}{4}[/tex])-4y=3
    [tex]\frac{-1}{4}y+ \frac{15}{4} =3[/tex]
    [tex]\frac{-1}{4}y+ \frac{15}{4} - \frac{15}{4} =3- \frac{15}{4}[/tex] [Subtract [tex]\frac{15}{4}[/tex] to both sides]
    [tex]\frac{-1}{4}y= \frac{-3}{4}[/tex]
    [tex]\frac{ \frac{-1}{4}y}{ \frac{-1}{4} }= \frac{\frac{-3}{4} }{ \frac{-1}{4}}[/tex] [Divide both sides by [tex]\frac{-1}{4}[/tex] ]
    y = 3

    Step 3: Substitute 3 for y in x = [tex]\frac{3}{4}y+ \frac{3}{4}[/tex]
    [tex]\frac{3}{4}y+ \frac{3}{4}[/tex]
    [tex]\frac{3}{4}(3)+ \frac{3}{4}[/tex]
    x = 3

  9. The two equations given in the question are

    4x _ 3y = 3
    And
    5x _ 4y = 3
    Multiplying the first equation by 4 and the second equation by 3, we get
    16x - 12y = 12
    15x - 12y = 9
    Subtracting the second equation from the first equation, we get
    x = 3

    I hope the above procedure is clear enough for you to understand. I hope that this is the answer that you were looking for and the answer has actually come to your great help.

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