We know the density for mercury is 13.6 g/mL, and we know the mass of the sample is 53.8 g. Thus, we can plug these numbers into our equation and solve for volume.
The volume is unknown, so we can simply denote it as "x"
[tex]13.6 g/mL=\frac{53.8 g}{x}[/tex]
multiply both sides by x
[tex](x)(13.6 g/mL)=\frac{53.8 g}{x}(x)[/tex]
The x's cancel out on the right side and you are left with
[tex](x)(13.6 g/mL)=53.8 g[/tex]
From here, simply divide both sides of the equation by 13.6 g/mL and solve for x.
D - density: 13.6 g/mL
m - mass: 76.5 g
V - volume: ???
d = m/V
V = m/d
V = 76.5/13,6
V = 5,625 mL
🙂
24 square root . i know im wrong but so what
energy required is 0.247kJ
Explanation:
The formula to use is Energy = nRdT;
Where n is number of mole
R is the molar gas constant
dT is the change in temperature
n = reacting mass of mercury / molar mass of mercury = 27.4/200.59 = 0.137
dT = final temperature - initial temperature = 376.20 - 158.30 = 217.90K
R = 8.314Jper mol per Kelvin
Energy = 0.137 x 8.314 x 217.90 = 247.12J
Energy in kJ= 247.12/1000= 0.247kJ
Hey there!
D = m / V
13.6 = 76.2 / V
V = 76.2 / 13.6
V = 5.602 mL
Units are all fine. No need of conversion.
Just Use the formula:
V = mass / density
V = 76.2 / 13.6 = 5.6 mL
* Density = 13.6 g/cm³
* Mass = 76.2 g
Volume = ?
D = m / V
13.6 = 76.2 / V
V = 76.2 / 13.6
V = 5.602 L
Volume is mass/density.
v=76.2g/14.184g/cms^3 (which I believe is the density of liquid mercury)
=5.37
its volume this is the answer because the mercury will turn into gas. gas has more volume because it takes up more space as it spreads.
53gm
Explanation:
The formula for density is:
[tex]density=\frac{mass}{volume}[/tex]
We know the density for mercury is 13.6 g/mL, and we know the mass of the sample is 53.8 g. Thus, we can plug these numbers into our equation and solve for volume.
The volume is unknown, so we can simply denote it as "x"
[tex]13.6 g/mL=\frac{53.8 g}{x}[/tex]
multiply both sides by x
[tex](x)(13.6 g/mL)=\frac{53.8 g}{x}(x)[/tex]
The x's cancel out on the right side and you are left with
[tex](x)(13.6 g/mL)=53.8 g[/tex]
From here, simply divide both sides of the equation by 13.6 g/mL and solve for x.
[tex]\frac{(x)13.6 g/mL}{13.6 g/mL}=\frac{53.8 g}{13.6 g/mL}[/tex]
[tex]x=3.955882353 mL[/tex]
Round to 3 significant figures, and your final answer is:
[tex]x=3.96 mL[/tex]
The volume of the sample of mercury was 3.96 mL.