What is the volume of a sample of liquid mercury that has a mass of 76.2g

What is the volume of a sample of liquid mercury that has a mass of 76.2g

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  1. energy required is 0.247kJ


    The formula to use is Energy = nRdT;

    Where n is number of mole

    R is the molar gas constant

    dT is the change in temperature

    n = reacting mass of mercury / molar mass of mercury = 27.4/200.59 = 0.137

    dT = final temperature - initial temperature = 376.20 - 158.30 = 217.90K

    R = 8.314Jper mol per Kelvin

    Energy = 0.137 x 8.314 x 217.90 = 247.12J

    Energy in kJ= 247.12/1000= 0.247kJ

  2. Volume is mass/density.
    v=76.2g/14.184g/cms^3 (which I believe is the density of liquid mercury)

  3. its volume this is the answer because the mercury will turn into gas. gas has more volume because it takes up more space as it spreads.

  4. The formula for density is:


    We know the density for mercury is 13.6 g/mL, and we know the mass of the sample is 53.8 g. Thus, we can plug these numbers into our equation and solve for volume.

    The volume is unknown, so we can simply denote it as "x"

    [tex]13.6 g/mL=\frac{53.8 g}{x}[/tex]

    multiply both sides by x

    [tex](x)(13.6 g/mL)=\frac{53.8 g}{x}(x)[/tex]

    The x's cancel out on the right side and you are left with

    [tex](x)(13.6 g/mL)=53.8 g[/tex]

    From here, simply divide both sides of the equation by 13.6 g/mL and solve for x.

    [tex]\frac{(x)13.6 g/mL}{13.6 g/mL}=\frac{53.8 g}{13.6 g/mL}[/tex]

    [tex]x=3.955882353 mL[/tex]

    Round to 3 significant figures, and your final answer is:

    [tex]x=3.96 mL[/tex]

    The volume of the sample of mercury was 3.96 mL.

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