What is what is the area of this face 10 inches 5 in 20 in 10 in 5 in 10

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What is what is the area of this face 10 inches 5 in 20 in 10 in 5 in 10

40

Step-by-step explanation:

edg 2020

Cirrhosis of the liver

Unlawful speed resulting in a collision

Have life-long disabilities

No period of time

Gender

10%

Under 40 inches

The recommended driving speed for that area

False

Behind the crossing symbol painted on the road

70 mph

Both

I would say false, but I’m not sure for this one

.03

The person might be in an emergency situation

False

A hospital zone

20 inches

.02

New Year’s Eve

.08

A felony for drug possession

True

Water builds up on the road

False

$1,000

Test your breaks when you get to the other side

Under any circumstances

Hope I helped!!

160 I think

Step-by-step explanation:

Choice D)

S(x) = 6x^2 - 20x

Explanation:

x = side length of base

x*x = x^2 = area of base

The top also has an area of x^2 since the base and top are both congruent squares. The total base area is x^2+x^2 = 2x^2

The height h is 5 inches shorter than the base, so

h = (base length) - 5

h = x-5

Each lateral side is of area h*x = (x-5)*x = x^2-5x

There are 4 lateral sides

Total lateral area = 4*(area of one lateral side)

Total lateral area = 4*(x^2-5x)

Total lateral area = 4*x^2-4*5x

Total lateral area = 4*x^2-20x

Add the total lateral area (4x^2-20x) to the total base area (2x^2)

Doing so gets us

S(x) = Total Surface Area

S(x) = (Area of bases) + (area of lateral sides)

S(x) = (2x^2) + (4x^2-20x)

S(x) = (2x^2+4x^2) - 20x

S(x) = 6x^2 - 20x

which is why the answer is choice D

The answer is the option C

Net A with [tex]510[/tex] square inches

Step-by-step explanation:

we know that

The surface area is equal to the sum of the areas of all the faces

In this problem the correct Net is the figure A

To find the surface area find the area of the [tex]3[/tex] rectangles plus the area of the [tex]2[/tex] triangles

so

Find the area of the [tex]3[/tex] rectangles

[tex]A1=13*15+12*15+5*15=450\ in^{2}[/tex]

Find the area of the [tex]2[/tex] triangles

[tex]A2=12*5/2+12*5/2=60\ in^{2}[/tex]

Adds the areas

[tex]450\ in^{2}+60\ in^{2}=510\ in^{2}[/tex]

B.)10 inches

you need to plug in 10

thats if you don't know what to do

the easy way

As far as I can tell you are right on all but the last one and the second one because you didn't answer. The last one you got the area of one face but there are 6, and the second one is 30.52 because you have to get 3 1/8 as a decimal which is 3.125 and then you cube it or multiply it by itself then the product by 3.125 again.

For the second question is c 16.4

for question 4 is D

Moma

Step-by-step explanation:

For the first one the answer is 2