This Post Has 4 Comments

1. Idkh nsnsnsnjdmdjfnbduxndb

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2. x= {±1,±√8}

   explanation:

   let

   x^2   = u

   so the equation will become:

   [tex]u^2-9u+8=0\\factorizing\\u^2-8u-u+8=0\\u(u-8)-1(u-8)=0\\(u-8)(u-1)=0[/tex]

   so,

   [tex]u-1=0\\u = 1u-8=0\\u=8[/tex]

   so, the solution in the form of u is (1,8)

   putting the substitution u=x^2 back

   [tex]x^2=1[/tex]

   [tex]\sqrt{x^2}=\sqrt{1}[/tex]

   x = ±1

   similarly,

   [tex]x^2=8\\\sqrt{x^2}=\sqrt{8}[/tex]

   x=±[tex]\sqrt{8}[/tex]

   ..

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3. i'm new here too we can chat if u like

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4. a and b!

   dfroos means which is a and b

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