Which equation can be used to solve for b? triangle a b c is shown. angle b c a is a right angle and angle c a b is 30 degrees. the length of side b c is 5 centimeters, the length of b a is 10 centimeters, and the length of c a is b. tan(30o) = startfraction 5 over b endfraction tan(30o) = startfraction b over 5 endfraction tan(30o) = startfraction 10 over b endfraction tan(30o) =

answer:

sometimes

*i think

Use photo math it it’s so good

We should use the correct formula for tan α (which is opposite

leg over adjacent leg) tan α = 5/b

Step-by-step explanation:

See attached file

We must use the for equation of tan α = BC/AC

tan α = BC/ b tan α = 5/b tan 30⁰ = 1/√3

b = 5/√3 ⇒ b = 5/1.7320

b = 2.8868 cm

[tex]tan30^{\circ}=\frac{5}{b}[/tex]

Step-by-step explanation:

We are given that a triangle ABC in which angle CAB=90 degrees

Angle CAB=30 degrees

Length of BC= 5 cm

Length of AB=10 cm

Length of AC=b

We have to find the equation which is used to solve for b.

We know that

[tex]tan\theta=\frac{Perpendicular\;side}{Base}[/tex]

Substitute the values

[tex]tan30^{\circ}=\frac{BC}{CA}[/tex]

[tex]tan30^{\circ}=\frac{5}{b}[/tex]

[tex]\frac{1}{\sqrt3}=\frac{5}{b}[/tex] ([tex]tan30^{\circ}=\frac{1}{\sqrt3}[/tex])

[tex]b=5\sqrt3[/tex]

Hence, the equation can be used to solve for b is given

[tex]tan30^{\circ}=\frac{5}{b}[/tex]

[tex]Which equation can be used to solve for b? triangle a b c is shown. angle b c a is a right angle an[/tex]