Which equation is in point-slope form and is depicted by the line in this graph?

(y−3)=3/5(x−2)

(y−3)=−3/5(x+2)

(y−3)=5/3(x−2)

(y+3)=5/3(x+2)

[tex]Which equation is in point-slope form and is depicted by the line in this graph? (y−3)=[/tex]

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Which equation is in point-slope form and is depicted by the line in this graph?

(y−3)=3/5(x−2)

(y−3)=−3/5(x+2)

(y−3)=5/3(x−2)

(y+3)=5/3(x+2)

[tex]Which equation is in point-slope form and is depicted by the line in this graph? (y−3)=[/tex]

(y−3)=−3/5(x+2) is the answer

The answer to your question is letter B

Step-by-step explanation:

Data

P (-2 , 3)

Q (3, 0)

Process

1.- Find the slope of the line

m = (0 -3) / (3 -(-2))

m = -3 / (3 + 2)

m = -3/5

2.- Find the equation of the line

Formula

y - y1 = m(x - x1)

Substitution

y - 3 = -3/5(x - (-2))

Simplification

y - 3 = -3/5(x + 2)

The first thing you should do in this case is to write the equation in its generic form.

We have then:

y-yo = m (x-xo)

We look for the slope:

m = (y2-y1) / (x2-x1)

m = (0-3) / (3 - (- 2))

m = -3 / 5

We choose any point of the line:

(xo, yo) = (- 2, 3)

We substitute the values in the generic equation:

y-3 = -3 / 5 (x - (- 2))

We rewrite:

y-3 = -3 / 5 (x + 2)

b) (y - 3) = - 3/5 (x + 2)

C is the answer

[tex]y-3=\frac{-3}{5}(x+2)[/tex]

Step-by-step explanation:

Points : (-2,3) and ( 3,0)

Let [tex](x_1,y_1)=(-2,3)[/tex]

[tex](x_2,y_2)=(3,0)[/tex]

Two point slope form : [tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

Substitute the given points.

[tex]y-3=\frac{0-3}{3-(-2)}(x-(-2))[/tex]

[tex]y-3=\frac{0-3}{3+2}(x+2)[/tex]

[tex]y-3=\frac{-3}{5}(x+2)[/tex]

Thus Option 2 is correct.

[tex]y-3=\frac{-3}{5}(x+2)[/tex] equation is in point-slope form and is depicted by the line in this graph

I hope this helps you

[tex]Which equation is in point-slope form and is depicted by the line in this graph? the points are (-2[/tex]

The correct answer would be B.i hope that helped

Y-y1=m(x-x1)

a point on the line is (x1,y1) and the slope is m

so

slope between (x1,y1) and (x2,y2) is (y2-y1)/(x2-x1)

so

points (-2,3) and (3,0)

slope is (0-3)/(3-(-2))=-3/(3+2)=-3/5

a point is (3,0) Or (-2,3)

so it could be

y-0=-3/5(x-3) or y-3=-3/5(x-(-2)) which is equal to y-3=-3/5(x+2)

that's the answer

B is answer

The answer is B, hope this helps