Which equation is in point-slope form and is depicted by the line in this graph?
(y−3)=3/5(x−2)
(y−3)=−3/5(x+2)
(y−3)=5/3(x−2)
(y+3)=5/3(x+2)
[tex]Which equation is in point-slope form and is depicted by the line in this graph? (y−3)=[/tex]
Which equation is in point-slope form and is depicted by the line in this graph?
(y−3)=3/5(x−2)
(y−3)=−3/5(x+2)
(y−3)=5/3(x−2)
(y+3)=5/3(x+2)
[tex]Which equation is in point-slope form and is depicted by the line in this graph? (y−3)=[/tex]
(y−3)=−3/5(x+2) is the answer
The answer to your question is letter B
Step-by-step explanation:
Data
P (-2 , 3)
Q (3, 0)
Process
1.- Find the slope of the line
m = (0 -3) / (3 -(-2))
m = -3 / (3 + 2)
m = -3/5
2.- Find the equation of the line
Formula
y - y1 = m(x - x1)
Substitution
y - 3 = -3/5(x - (-2))
Simplification
y - 3 = -3/5(x + 2)
The first thing you should do in this case is to write the equation in its generic form.
We have then:
y-yo = m (x-xo)
We look for the slope:
m = (y2-y1) / (x2-x1)
m = (0-3) / (3 - (- 2))
m = -3 / 5
We choose any point of the line:
(xo, yo) = (- 2, 3)
We substitute the values in the generic equation:
y-3 = -3 / 5 (x - (- 2))
We rewrite:
y-3 = -3 / 5 (x + 2)
b) (y - 3) = - 3/5 (x + 2)
C is the answer
[tex]y-3=\frac{-3}{5}(x+2)[/tex]
Step-by-step explanation:
Points : (-2,3) and ( 3,0)
Let [tex](x_1,y_1)=(-2,3)[/tex]
[tex](x_2,y_2)=(3,0)[/tex]
Two point slope form : [tex]y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
Substitute the given points.
[tex]y-3=\frac{0-3}{3-(-2)}(x-(-2))[/tex]
[tex]y-3=\frac{0-3}{3+2}(x+2)[/tex]
[tex]y-3=\frac{-3}{5}(x+2)[/tex]
Thus Option 2 is correct.
[tex]y-3=\frac{-3}{5}(x+2)[/tex] equation is in point-slope form and is depicted by the line in this graph
I hope this helps you
[tex]Which equation is in point-slope form and is depicted by the line in this graph? the points are (-2[/tex]
The correct answer would be B.i hope that helped
Y-y1=m(x-x1)
a point on the line is (x1,y1) and the slope is m
so
slope between (x1,y1) and (x2,y2) is (y2-y1)/(x2-x1)
so
points (-2,3) and (3,0)
slope is (0-3)/(3-(-2))=-3/(3+2)=-3/5
a point is (3,0) Or (-2,3)
so it could be
y-0=-3/5(x-3) or y-3=-3/5(x-(-2)) which is equal to y-3=-3/5(x+2)
that's the answer
B is answer
The answer is B, hope this helps