# Which intervals show f(x) increasing? Choose two options

Which intervals show f(x) increasing? Choose two options

## This Post Has 10 Comments

1. infoneetusinghoyg22o says:

2. aydenmasonc says:

[–2.5, –1.6):

Check the picture attached. The half closed interval of x, [–2.5, –1.6) is shown with the red line segment.

The part of the graph corresponding to this interval is also shown. f(-2.5)<f(-2,4)      so f (x) in not increasing in the first interval.

second interval, [–2, –1]: in this interval, f(x) is decreasing.

(for larger values of x in this interval, the graphs decreases continuously, that is f(x) decreases.

third interval, (–1.6, 0]:

The graph decreases for x from -1,6 up to a value close to -0.5. Then from this value to 0, the graph is constant.

So f(x) is not increasing.

the fourth interval [0, 0.8):

This interval is shown by the purple line segment. Similar to the third case, in this interval for approximately half of the first values of x, f(x) is constant, then in the second half, f(x) is increasing.

(0.8, 2)

in this interval, for larger x, we have larger f(x), so the function is increasing.

(0.8, 2)

$Which intervals show f(x) increasing? check all that apply. [–2.5, –1.6) [–2, –1] (–1.6, 0] [0, 0.8$

3. camilaird says:

The correct options are 3 and 4.

Explanation:

From the given graph it is clear that the turning points of the graph are (-1.6,-56), (0.8,11.4) and (2,0).

Using these points we can say that,

1. The given function increasing on $(-1.6,0.8),(2,\infty)$.

2.The function is decreasing on $(-\infty,-1.6),(0.8,2)$.

In interval [–2.5, –1.6), the function is decreasing.

In interval [–2, –1], first the function is decreases, after that the function increases.

In interval (–1.6, 0], the function is decreasing.

In interval [0, 0.8), the function is decreasing.

In interval (0.8, 2), the function is decreasing.

Therefore, the correct options are 3 and 4.

Ithink the answer a b c e

5. aliyahlknox881 says:

The correct options are 3 and 4.

Explanation:

From the given graph it is clear that the turning points of the graph are (-1.6,-56), (0.8,11.4) and (2,0).

Using these points we can say that,

1. The given function increasing on $(-1.6,0.8),(2,\infty)$.

2.The function is decreasing on $(-\infty,-1.6),(0.8,2)$.

In interval [–2.5, –1.6), the function is decreasing.

In interval [–2, –1], first the function is decreases, after that the function increases.

In interval (–1.6, 0], the function is decreasing.

In interval [0, 0.8), the function is decreasing.

In interval (0.8, 2), the function is decreasing.

Therefore, the correct options are 3 and 4.

6. only1kariyah says:

For this case what you should do is take into account the average rate of change.

By definition we have the average rate of change is:

$AVR = \frac{f(x2)-f(x1)}{x2-x1}$

Therefore, the function is growing for the intervals where it is fulfilled:

$AVR 0$

These growth intervals are given by:

(-1.6, 0]

[0, 0.8)

The intervals that show f (x) increasing are:

(-1.6, 0]

[0, 0.8)

7. diamondgdm says:

its c and d

Step-by-step explanation:

i know things...

8. puppylover72 says:

It depends, because there are many possibilities for answers.

9. twinkie7078 says:

(-1.6, 0)

(0, 0.8)

Step-by-step explanation:

10. depaze6652 says:

option C and option D the function f(x) is increasing.

Step-by-step explanation:

" A graph is said to be increasing in an interval if it's value keeps on increasing in that particular interval ".

By looking at the graph attached in the question we could clearly see that the function f(x) is increasing in the interval (-1.6,0] and [0,0.8).

and in all the rest options asked in the question the function f(x) is decreasing.

Hence, for option C and option D the function f(x) is increasing.