Which is a correct statement about the description “six less than the quotient of a number cubed and nine, increased by twelve” when n = 3? check all that apply. the correct expression is . the correct expression is . one of the steps to determining the value when n = 3 is . one of the steps to determining the value when n = 3 is . the value when n = 3 is 7. the value when n = 3 is 9. the value when n = 3 is 15. the value when n = 3 is 17.

The value when n = 3 is 9

Step-by-step explanation:

Given : six less than the quotient of a number cubed and nine, increased by twelve”

Solution:

let number be n

Since we are given that “six less than the quotient of a number cubed and nine, increased by twelve”

⇒[tex](\frac{n^{3}}{9} -6)+12[/tex]

Now put the value of n =3

⇒[tex](\frac{3^{3}}{9} -6)+12[/tex]

⇒[tex](\frac{27}{9} -6)+12[/tex]

⇒[tex](3 -6)+12[/tex]

⇒[tex]-3+12[/tex]

⇒[tex]9[/tex]

Thus option 2 is correct. The value when n = 3 is 9

The correct expression is StartFraction n cubed Over 9 EndFraction minus 6 + 12.

The correct expression is: [tex]\frac{n^3}{9}-6+12[/tex]

One of the step to determining the value when [tex]n=3[/tex] is [tex]3-6+12[/tex]

The value when [tex]n=3[/tex] is [tex]9[/tex].

Step-by-step explanation:

Six less than the quotient of a number cubed and nine, increased by twelve.

Let the number be [tex]=n[/tex]

The mathematical expression of the statement can be written as:

[tex]\frac{n^3}{9}-6+12[/tex]

Evaluating the expression when [tex]n=3[/tex]

[tex]=\frac{3^3}{9}-6+12[/tex]

[tex]=\frac{27}{9}-6+12[/tex]

[tex]=3-6+12[/tex]

[tex]=9[/tex]

∴ The value when [tex]n=3[/tex] is [tex]9[/tex].

The answer is A. C(might be D ask your teacher if it's C or D), and F so F is 9 C is n=3 is 3-6+12 D is n=3 is 6-3+12 and A is 6-n3/9

Step-by-step explanation:

The answer is/ would be all of that, that is above.

1,4,6

Step-by-step explanation:

The correct equation should be (3^3)/9-6 +12 if it is written correctly.

The answer would be 9