Which of the following is the correct factorization of the polynomial below?
2x2 - 16x+ 32
O A. (2x+4)(x+2)
O B. 2(x+2)(x+8)
O c. 2(x-4)2
O D. The polynomial is irreducible.
Which of the following is the correct factorization of the polynomial below?
2x2 - 16x+ 32
O A. (2x+4)(x+2)
O B. 2(x+2)(x+8)
O c. 2(x-4)2
O D. The polynomial is irreducible.
Here given a quadratic polynomial
we have to factorize it
2x²-8x+8
take 2 as common
2(x²-4x+4)
Here x²-4x+4 can also be written as
(x-2)²= x²-2×2×x +(2)²
(x-3
2)²= x²-4x+4
Hence ,
2(x-2)² is our answer
Option C is the correct option
B
Step-by-step explanation:
I think the answer is B.
The polynomial is irreducible
Step-by-step explanation:
There is nothing we can subtract between x3-12
For example: you are trying to find the polynomial of x4-6
Options:
A. (x+4)(x-6)
B. (x+1+3)(x-6)
C. None the polynomial is irreducible.
You would chose C because there is no subtraction sign in between the parentheses. If you would choose a right answer, you would rewrite it as:
(x+4)-(6)
Answer option C
27x³+64y³
it's written as
(3x)³ +(4y)³
Now by using identify
a³+b³=(a+b)(a²-ab+b²)
(3x)³+(4y)³= (3x+4y){(3x)² - 3x*4y+(4y)²}
→ (3x+4y)( 9x²-12xy+16y²)
So required answer is option C
(21xy +15x )+ (35ry +25r)
3x(7y+5)+ 5r(7y+5)
(3x+5r)(7y+5)
Please rate
the correct option is
(B) [tex](4x+3)(16x^2-12x+9).[/tex]
Step-by-step explanation: We are given to select the correct factorization of the following polynomial :
[tex]P=64x^3+27.[/tex]
We will be using the following factorization formula :
[tex]a^3+b^3=(a+b)(a^2-ab+b^2).[/tex]
Therefore, the factorization of the given polynomial is as follows :
[tex]P\\\\=64x^3+27\\\\=(4x)^3+3^3\\\\=(4x+3)((4x)^2-4x\times3+3^2)\\\\=(4x+3)(16x^2-12x+9).[/tex]
Thus, the required factored form is [tex](4x+3)(16x^2-12x+9).[/tex]
Option (B) is CORRECT.
C. 2(x-4)^2
Step-by-step explanation:
To factorize 2x^2-16x+32
We have to take it step by step and know if it's factorizable then if it is we will look for the answer.
2x^2-16x+32 = 2x² -16x +(2x²)(32)
2x^2-16x+32= 2x² -16x +64x²
I'll ask myself what do i multiply to give me +64x² and add to get -16x.
It's simple.
The answer is -8x
-8x *-8x = 64x²
-8x+-8x = -16x
2x^2-16x+32= 2x² -16x +32
2x^2-16x+32=2x²-8x-8x+32
2x^2-16x+32= 2x(x-4)-8(x-4)
2x^2-16x+32=(2x-8)(x-4)
2x^2-16x+32=2(x-4)(x-4)
2x^2-16x+32=2(x-4)²
64x^3 + 27 is a sum of cubes: (4x)^3 + 3^3, for which the factors are (4x + 3)(16x^2 - 12x + 9)
correct answer is B.(2x+3y)(4x^2-6xy+9y^2)
8x^3 + 27y^3
(2x)^3+(3y)^3
(2x+3y)(4x^2-6xy+9y^2) <answer