This Post Has 10 Comments

1. c

   Step-by-step explanation:

   most of the people will spam to get points

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2. no solution

   Step-by-step explanation:

   hope this helped have a great day 😀

   Reply

3. there is not a solution to that problem

   so it would be A

   Reply

4. a

   Step-by-step explanation:

   Reply

5. (4, 2)

   General Formulas and Concepts:

   Pre-Algebra

   Order of Operations: BPEMDAS

   Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

   Equality Properties

   Algebra I

   TermsSolving systems of equations using substitution/elimination

   Step-by-step explanation:

   Step 1: Define Systems

   -2x + 2y = -4

   2x - 3y = 2

   Step 2: Rewrite Systems

   2x - 3y = 2

   Add 3y to both sides:                    2x = 3y + 2

   Step 3: Redefine Systems

   -2x + 2y = -4

   2x = 3y + 2

   Step 4: Solve for y

   Substitution

   Substitute in 2x:                    -(3y + 2) + 2y = -4Distribute -1:                           -3y - 2 + 2y = -4Combine like terms:              -y - 2 = -4Isolate y term:                        -y = -2Isolate y:                                 y = 2

   Step 5: Solve for x

   Define equation:                    2x - 3y = 2Substitute in y:                       2x - 3(2) = 2Multiply:                                  2x - 6 = 2Isolate x term:                        2x = 8Isolate x:                                 x = 4

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6. Arrange in slope intercept form
   2y = 2x -4
   y = x - 2

   So, the line would go upcrossing the y axis at -2hope this helps

   Reply

7. x=4, y=2 (4,2)

   Step-by-step explanation:

   This is a system of equations.

   -2x+2y=-4

   2x-3y=2

   I'll use the elimination method to solve this.

   add the two equations together.

   what's left:

   -y=-2

   multiply both by -1

   y=2

   now, substitute 2 as y into one of the other equations.

   For example:

   -2x+2(2)=-4

   -2x+4=-4

   -2x=-8

   x=4

   hope this helps!

   Reply

8. no solution

   Step-by-step explanation:

   To put the first equation into standard form, with the coefficients mutually prime, divide it by 5:

   ... x - y = 4

   To put the second equation into standard form, with the coefficients mutually prime and the leading coefficient positive, divide by -2:

   ... x - y = 2

   These are inconsistent equations, hence have no solution.

   Reply

9.   (x, y) = (-2, -4)

   Step-by-step explanation:

   I like to start by putting the equations into standard form. That requires removing any common factors and making the leading coefficient positive.

     -2x +2y = -4   ⇒   x -y = 2 . . . . . . divide by -2

     3x +3y = -18   ⇒   x +y = -6 . . . . . divide by 3

   __

   Now, we can add these two equations to eliminate y:

     (x -y) +(x +y) = (2) +(-6)

     2x = -4 . . . . simplify

     x = -2 . . . . . divide by 2

   Substituting into the second equation gives ...

     -2 +y = -6

     y = -4 . . . . . add 2

   The solution to the system of equations is (x, y) = (-2, -4).

   [tex]Find the solution to the system of equation -2x+2y=-4 3x+3y=-18[/tex]

   Reply

10. x=0 and y=−2

    keep scrolling it is kind of long

    Step-by-step explanation:

    −2x+2y=−4,3x−2y=4

    −2x+2y=−4for x:

    −2x+2y=−4

    −2x+2y+−2y=−4+−2y

    −2x=−2y−4

    -2x/-2=-2y-4/-2

    x=y+2

    Substitute y +2 for x in3x−2y=4:

    3x−2y=4

    3(y+2)−2y=4

    y+6=4

    y+6+−6=4+−6

    y=−2

    Substitute −2 for y in x=y+2:

    x=y+2

    x=−2+2

    x=0

    x=0 and y=−2

    Reply