Which ordered pairs are solutions to the inequality –3x + y ≥ 7?

choose all answers that are correct.

(–2, –3)

(3, 18)

(0, 7)

(1, 9)

(–1, 8)

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choose all answers that are correct.

(–2, –3)

(3, 18)

(0, 7)

(1, 9)

(–1, 8)

Q1. The answers are (–1, 8), (0, 7), (3, 18)

–3x + y ≥ 7

Let's go through all choices:

(–2, –3)

(-3) * (-2) + (-3) ≥ 7

6 - 3 ≥ 7

3 ≥ 7 INCORRECT

(–1, 8)

(-3) * (-1) + 8 ≥ 7

3 + 8 ≥ 7

11 ≥ 7 CORRECT

(0, 7)

(-3) * 0 + 7 ≥ 7

0 + 7 ≥ 7

7 ≥ 7 CORRECT

(1, 9)

(-3) * 1 + 9 ≥ 7

-3 + 9 ≥ 7

6 ≥ 7 INCORRECT

(3, 18)

(-3) * 3 + 18 ≥ 7

-9 + 18 ≥ 7

9 ≥ 7 CORRECT

Q2. The answers are:

5x + 12y ≤ 80

x ≥ 4

y ≥ 0

x - small boxes

y - large boxes

He has x small boxes that weigh 5 lb each and y large boxes that weigh 12 lb each on a shelf that holds up to 80 lb:

5x + 12y ≤ 80

Jude needs at least 4 small boxes on the shelf: x ≥ 4

Let's check if y can be 0:

5x + 12y ≤ 80

5x + 12 * 0 ≤ 80

5x + 0 ≤ 80

5x ≤ 80

x ≤ 80 / 5

x ≤ 16

x ≥ 4 can include x ≤ 16

So, y can be 0: y ≥ 0