Which reason justifies the statement that klc is complementary to kjc?

[tex]Which reason justifies the statement that klc is complementary to kjc?[/tex]

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Which reason justifies the statement that klc is complementary to kjc?

[tex]Which reason justifies the statement that klc is complementary to kjc?[/tex]

we know that

m∠KJM=m∠KLM=[tex]90[/tex]°

m∠KJC=m∠MLC -----> equation [tex]1[/tex]

m∠KJM=m∠KJC+m∠CJM=[tex]90[/tex]° -----> equation [tex]2[/tex]

m∠KLM=m∠KLC+m∠MLC=[tex]90[/tex]° -----> equation [tex]3[/tex]

Substitute equation [tex]1[/tex] in equation [tex]3[/tex]

So

m∠KLM=m∠KLC+[m∠KJC]=[tex]90[/tex]°

angles ∠KLC and ∠KJC------> are complementary angles

therefore

the answer is

Angles that are congruent are complementary to the same angle

Complementary angles are angles that sum up to 90°

We know that:

1- MLC=KJC.

2- KLM=90.

KLM is composed of KLC and MLC.

This means that:

KLC+MLC=90°

Since MLC=KJC, we can write this as KLC+KJC=90°.

This is the definition of complementary (two angles whose sum is 90 degrees).

Angles that are congruent are complementary to the same angle

Step-by-step explanation:

see that attached figure to better understand the problem

we know that

Two angles are complementary if their sum is equal to [tex]90\°[/tex]

[tex]m<KJM=m<KLM=90\°[/tex]

[tex]m<KJC=m<MLC[/tex] -----> equation A

[tex]m<KJM=m<KJC+m<CJM[/tex]

so

[tex]m<KJC+m<CJM=90\°[/tex] -----> equation B

[tex]m<KLM=m<KLC+m<MLC[/tex]

so

[tex]m<KLC+m<MLC=90\°[/tex] -----> equation C

Substitute equation A in equation C

So

[tex]m<KLC+[m<KJC]=90\°[/tex]

That means------> angles ∠KLC and ∠KJC------> are complementary angles

therefore

the answer is

Angles that are congruent are complementary to the same angle

[tex]Figure jklm is a rectangle, so mkjm = mklm = 90° and kjc mlc. which reason justifies the statement t[/tex]

a) Angles that are congruent are complementary to the same angle

Step-by-step explanation:

Considering the figure attached:

Two angles are complementary if their sum is 90°

given that :

∠KJM = ∠KLM = 90° --- (1)

∠KJC ≅ ∠MLC

⇒ ∠KJC = ∠MLC ---- (2)

∠KJM = ∠KJC + ∠CJM

so by (1) above eq becomes

∠KJC + ∠CJM = 90° --- (3)

Similarly for ∠KLM

∠KLM = ∠KLC + ∠MLC

∠KLC + ∠MLC = 90° ---- (4)

Substitute (2) in (4)

∠KLC + ∠KJC = 90°

Which proves that ∠KLC and ∠KJC are complementary angles

So,

Angles that are congruent are complementary to the same angle

[tex]Figure jklm is a rectangle, so mkjm = mklm = 90° and kjc mlc.which reason justifies the statement th[/tex]

Angles that are congruent are complementary to the same angle

Step-by-step explanation:

see that attached figure to better understand the problem

we know that

Two angles are complementary if their sum is equal to [tex]90\°[/tex]

[tex]m<KJM=m<KLM=90\°[/tex]

[tex]m<KJC=m<MLC[/tex] -----> equation A

[tex]m<KJM=m<KJC+m<CJM[/tex]

so

[tex]m<KJC+m<CJM=90\°[/tex] -----> equation B

[tex]m<KLM=m<KLC+m<MLC[/tex]

so

[tex]m<KLC+m<MLC=90\°[/tex] -----> equation C

Substitute equation A in equation C

So

[tex]m<KLC+[m<KJC]=90\°[/tex]

That means------> angles ∠KLC and ∠KJC------> are complementary angles

therefore

Angles that are congruent are complementary to the same angle

[tex]Which reason justifies the statement that klc is complementary to kjc?[/tex]

Angles that are congruent are complementary to the same angle. Is the correct answer A

Angles that are congruent are complementary to the same angle

Step-by-step explanation:

see that attached figure to better understand the problem

we know that

Two angles are complementary if their sum is equal to [tex]90\°[/tex]

[tex]m[/tex]

[tex]m[/tex] -----> equation A

[tex]m[/tex]

so

[tex]m[/tex] -----> equation B

[tex]m[/tex]

so

[tex]m[/tex] -----> equation C

Substitute equation A in equation C

So

[tex]m[/tex]

That means------> angles ∠KLC and ∠KJC------> are complementary angles

therefore

the answer is

Angles that are congruent are complementary to the same angle

[tex]Which reason justifies the statement that klc is complementary to kjc? angles that are congruent ar[/tex]

Angles that are congruent are complementary to the same angle

Step-by-step explanation:

we know that

Two angles are complementary if their sum is equal to [tex]90\°[/tex]

[tex]m<KJM=m<KLM=90\°[/tex]

[tex]m<KJC=m<MLC[/tex] -----> equation A

[tex]m<KJM=m<KJC+m<CJM[/tex]

so

[tex]m<KJC+m<CJM=90\°[/tex] -----> equation B

[tex]m<KLM=m<KLC+m<MLC[/tex]

so

[tex]m<KLC+m<MLC=90\°[/tex] -----> equation C

Substitute equation A in equation C

So

[tex]m<KLC+[m<KJC]=90\°[/tex]

That means------> angles ∠KLC and ∠KJC------> are complementary angles

therefore

Angles that are congruent are complementary to the same angle

Where is the question

Angles that are congruent are complementary to the same angle.

Step-by-step explanation: