Which reason justifies the statement that klc is complementary to kjc?
[tex]Which reason justifies the statement that klc is complementary to kjc?[/tex]
Which reason justifies the statement that klc is complementary to kjc?
[tex]Which reason justifies the statement that klc is complementary to kjc?[/tex]
we know that
m∠KJM=m∠KLM=[tex]90[/tex]°
m∠KJC=m∠MLC -----> equation [tex]1[/tex]
m∠KJM=m∠KJC+m∠CJM=[tex]90[/tex]° -----> equation [tex]2[/tex]
m∠KLM=m∠KLC+m∠MLC=[tex]90[/tex]° -----> equation [tex]3[/tex]
Substitute equation [tex]1[/tex] in equation [tex]3[/tex]
So
m∠KLM=m∠KLC+[m∠KJC]=[tex]90[/tex]°
angles ∠KLC and ∠KJC------> are complementary angles
therefore
the answer is
Angles that are congruent are complementary to the same angle
Complementary angles are angles that sum up to 90°
We know that:
1- MLC=KJC.
2- KLM=90.
KLM is composed of KLC and MLC.
This means that:
KLC+MLC=90°
Since MLC=KJC, we can write this as KLC+KJC=90°.
This is the definition of complementary (two angles whose sum is 90 degrees).
Angles that are congruent are complementary to the same angle
Step-by-step explanation:
see that attached figure to better understand the problem
we know that
Two angles are complementary if their sum is equal to [tex]90\°[/tex]
[tex]m<KJM=m<KLM=90\°[/tex]
[tex]m<KJC=m<MLC[/tex] -----> equation A
[tex]m<KJM=m<KJC+m<CJM[/tex]
so
[tex]m<KJC+m<CJM=90\°[/tex] -----> equation B
[tex]m<KLM=m<KLC+m<MLC[/tex]
so
[tex]m<KLC+m<MLC=90\°[/tex] -----> equation C
Substitute equation A in equation C
So
[tex]m<KLC+[m<KJC]=90\°[/tex]
That means------> angles ∠KLC and ∠KJC------> are complementary angles
therefore
the answer is
Angles that are congruent are complementary to the same angle
[tex]Figure jklm is a rectangle, so mkjm = mklm = 90° and kjc mlc. which reason justifies the statement t[/tex]
a) Angles that are congruent are complementary to the same angle
Step-by-step explanation:
Considering the figure attached:
Two angles are complementary if their sum is 90°
given that :
∠KJM = ∠KLM = 90° --- (1)
∠KJC ≅ ∠MLC
⇒ ∠KJC = ∠MLC ---- (2)
∠KJM = ∠KJC + ∠CJM
so by (1) above eq becomes
∠KJC + ∠CJM = 90° --- (3)
Similarly for ∠KLM
∠KLM = ∠KLC + ∠MLC
∠KLC + ∠MLC = 90° ---- (4)
Substitute (2) in (4)
∠KLC + ∠KJC = 90°
Which proves that ∠KLC and ∠KJC are complementary angles
So,
Angles that are congruent are complementary to the same angle
[tex]Figure jklm is a rectangle, so mkjm = mklm = 90° and kjc mlc.which reason justifies the statement th[/tex]
Angles that are congruent are complementary to the same angle
Step-by-step explanation:
see that attached figure to better understand the problem
we know that
Two angles are complementary if their sum is equal to [tex]90\°[/tex]
[tex]m<KJM=m<KLM=90\°[/tex]
[tex]m<KJC=m<MLC[/tex] -----> equation A
[tex]m<KJM=m<KJC+m<CJM[/tex]
so
[tex]m<KJC+m<CJM=90\°[/tex] -----> equation B
[tex]m<KLM=m<KLC+m<MLC[/tex]
so
[tex]m<KLC+m<MLC=90\°[/tex] -----> equation C
Substitute equation A in equation C
So
[tex]m<KLC+[m<KJC]=90\°[/tex]
That means------> angles ∠KLC and ∠KJC------> are complementary angles
therefore
Angles that are congruent are complementary to the same angle
[tex]Which reason justifies the statement that klc is complementary to kjc?[/tex]
Angles that are congruent are complementary to the same angle. Is the correct answer A
Angles that are congruent are complementary to the same angle
Step-by-step explanation:
see that attached figure to better understand the problem
we know that
Two angles are complementary if their sum is equal to [tex]90\°[/tex]
[tex]m[/tex]
[tex]m[/tex] -----> equation A
[tex]m[/tex]
so
[tex]m[/tex] -----> equation B
[tex]m[/tex]
so
[tex]m[/tex] -----> equation C
Substitute equation A in equation C
So
[tex]m[/tex]
That means------> angles ∠KLC and ∠KJC------> are complementary angles
therefore
the answer is
Angles that are congruent are complementary to the same angle
[tex]Which reason justifies the statement that klc is complementary to kjc? angles that are congruent ar[/tex]
Angles that are congruent are complementary to the same angle
Step-by-step explanation:
we know that
Two angles are complementary if their sum is equal to [tex]90\°[/tex]
[tex]m<KJM=m<KLM=90\°[/tex]
[tex]m<KJC=m<MLC[/tex] -----> equation A
[tex]m<KJM=m<KJC+m<CJM[/tex]
so
[tex]m<KJC+m<CJM=90\°[/tex] -----> equation B
[tex]m<KLM=m<KLC+m<MLC[/tex]
so
[tex]m<KLC+m<MLC=90\°[/tex] -----> equation C
Substitute equation A in equation C
So
[tex]m<KLC+[m<KJC]=90\°[/tex]
That means------> angles ∠KLC and ∠KJC------> are complementary angles
therefore
Angles that are congruent are complementary to the same angle
Where is the question
Angles that are congruent are complementary to the same angle.
Step-by-step explanation: