Which rigid transformation would map δabc to δabf? a rotation about point a a reflection across the line containing cb a reflection across the line containing ba a rotation about point b

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Which rigid transformation would map δabc to δabf? a rotation about point a a reflection across the line containing cb a reflection across the line containing ba a rotation about point b

a rotation about point C

Step-by-step explanation:

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Option: D is the correct answer.

D) a rotation about point C.

Step-by-step explanation:

In order to map the figure ABC which act as a pre-image to the image EDC the transformation that will take place is:

A rotation about point C.

Since, when we fix the point C and the figure is rotated about the point C then the side AB is rotated to form side ED and side BC is mapped to side DC.

Hence, we can easily obtain our transformed image.

The answer is C 🙂

Explanation:

I hope this helps you out!!!

In the instructions it states ABC is reflected over line BA. So the rigid transformation is "a reflection across the line containing BA"

The answer is C 🙂

Explanation:

I hope this helps you out!!!

a reflection across the line containing BA

Step-by-step explanation:

The correct option C. The figure shows the a reflection across the line containing BA.

Explanation:

The rigid transforms means reflection, dilation and transformation.

In the given figure the two triangles are given ABC and ABF.

[tex]CA=FA[/tex]

[tex]\angle CAB=\angle FAB[/tex]

[tex]AB=AB[/tex]

So by SAS the triangle CAB and FAB are congruent.

The common side is BA, so the figure shows the a reflection across the line containing BA. The point C and F are equal distance from the line BA. AS shown in below figure.

From the figure it is easily noticed that the triangle FAB is the mirror image of triangle CAB across the side AB.

Therefore the correct option is C.

The correct option C. The figure shows the a reflection across the line containing BA.

Explanation:

The rigid transforms means reflection, dilation and transformation.

In the given figure the two triangles are given ABC and ABF.

[tex]CA=FA[/tex]

[tex]\angle CAB=\angle FAB[/tex]

[tex]AB=AB[/tex]

So by SAS the triangle CAB and FAB are congruent.

The common side is BA, so the figure shows the a reflection across the line containing BA. The point C and F are equal distance from the line BA. AS shown in below figure.

From the figure it is easily noticed that the triangle FAB is the mirror image of triangle CAB across the side AB.

Therefore the correct option is C.

its c

its c